4

我正在将 spring-data JPA 与休眠一起使用。我很难让我的继承和关系映射正常工作。

@Entity
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@Table(name="compound")
@DiscriminatorColumn(name="compound_type")
@DiscriminatorOptions(force=true)
public abstract class Compound<T extends Containable> {

    @OneToMany(fetch = FetchType.EAGER, mappedBy = "pk.compound",
        cascade = CascadeType.ALL, orphanRemoval = true)
    @LazyCollection(LazyCollectionOption.FALSE)     
    private List<CompoundComposition> compositions = new ArrayList<>(); 

    @OneToMany(fetch = FetchType.EAGER, mappedBy="compound",
        targetEntity=Containable.class, cascade = CascadeType.ALL) 
    @LazyCollection(LazyCollectionOption.FALSE)     
    private Set<T> containables = new HashSet<T>();

}

@Entity
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@Table(name="containable")
@DiscriminatorColumn(name="containable_type")
@DiscriminatorOptions(force=true)
public abstract class Containable<T extends Compound> {     

    @ManyToOne(optional=true, fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    private T compound;
}

这个想法是 AbstractCompound 的某个实现只能与 Containable 的一个特定实现相关联(反之亦然)。这导致以下实现:

@Entity 
@DiscriminatorValue("TestCompound") 
public class TestCompound extends AbstractCompound<TestContainable> {
}

@Entity 
@DiscriminatorValue("RegistrationCompound")
public class RegistrationCompound extends AbstractCompound<Batch> {

    @Column(name = "reg_number", unique = true)
    private String regNumber;
}

@Entity 
@DiscriminatorValue("TestContainable")  
public class TestContainable extends Containable<TestCompound> {
}

@Entity 
@DiscriminatorValue("Batch")    
public class Batch extends Containable<RegistrationCompound>{

    @Column(name = "batch_number")
    private Integer batchNumber;
}

我玩过所有的继承策略,对于复合层次结构,单表是唯一至少部分有效的策略。在 JOINED 或表 _per_class 休眠的情况下创建不一致和错误!!!外键,即从 test_containable 到 registration_compound(但不是从 Batch 到 test_compound,这里它仅正确映射到 registration_compound)。

在 Containable 方面,我使用什么策略似乎并不重要。

现在到我的测试中的实际问题。具体的测试类。有3个测试。所有人都在对“TestCompound”实例进行特定搜索。问题是这 3 个测试用例中的第一个执行总是通过,其他 2 个总是失败。运行的顺序似乎是随机的(JUnit + @RunWith(SpringJUnit4ClassRunner.class))。这意味着任何测试都通过,如果它是第一个运行的。

失败的测试抛出以下异常:

org.hibernate.WrongClassException: Object with id: 1000 was not of the specified
    subclass: RegistrationCompound (loaded object was of wrong class class TestCompound)

在第一次测试的情况下,在正确选择用于获取 Containables 后出现休眠问题

Hibernate: select containabl0_.compound_id as compound8_1_1_, containabl0_.id as id0_1_, 
containabl0_.id as id0_0_, containabl0_.created as created0_0_, 
containabl0_.created_by as created4_0_0_, containabl0_.last_modified as last5_0_0_, 
containabl0_.last_modified_by as last6_0_0_, containabl0_.compound_id as compound8_0_0_, 
containabl0_.batch_number as batch7_0_0_, containabl0_.containable_type as containa1_0_0_ 
from containable containabl0_ where  containabl0_.containable_type in ('Batch', 'TestContainable') 
and containabl0_.compound_id=?

并且List<CompoundComposition> compositions在另一个选择语句中被选中。所以它们总共是 3 条语句:获取化合物、获取可包含物、获取组合物。

对于第二个和第三个测试,用于获取可包含项的 SQL 与用于获取组合的 on 合并,并且它的构建方式是尝试选择 RegistrationCompound 而不是 TestCompound,例如它包含

registrati1_.reg_number as reg10_1_0_, 

并且 reg_number 只是 RegistrationCompound 的属性。在这两种情况下,第一个正确选择实际化合物的 select 语句在 where 子句中包含以下内容:

testcompou0_.compound_type='TestCompound'

所以这非常令人困惑。为什么它取决于运行测试的顺序?为什么它会尝试选择 RegistrationCompound?

这是 3 个测试中最简单的测试:

@Test
@Transactional
public void testFindByCompositionPkStructureId() {
    System.out.println("findByCompositionPkStructureId");

    Long structureId = 1000L;

    TestCompound compound = new TestCompound();
    compound.setId(1000L);
    compound.setCas("9999-99-9");
    compound.setCompoundName("Test Compound");

    List<TestCompound> result = 
        testCompoundRepository.findByCompositionsPkStructureId(structureId);
    assertEquals(compound, result.get(0));
}

如果此测试作为第二个或第三个运行,我会得到错误的类异常!!!有谁知道这里到底发生了什么?解决方案?

4

1 回答 1

7

问题是映射之一:

@Entity
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@Table(name="containable")
@DiscriminatorColumn(name="containable_type")
@DiscriminatorOptions(force=true)
public abstract class Containable<T extends Compound> {     

    @ManyToOne(optional=true, fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    private T compound;
}

此映射缺少目标实体。正确的是

@ManyToOne(optional=true, fetch = FetchType.EAGER, cascade = CascadeType.ALL, targetEntity = Compound.class)

由于某种原因,hibernate 只是假设目标是RegistrationCompound而不是抛出异常。很烦人,否则很容易找到问题。但就像这样,它几乎让我发疯了。

于 2013-02-17T09:01:39.773 回答