1

我想从给定日期获取周一到周五的周日期。

假设给定日期是 6-2-2013

我想要结果：

Monday    4-2-2013
Tuesday   5-2-2013
Wednesday 6-2-2013
Thursday  7-2-2013
Friday    8-2-2013

或者甚至我的第 6 周...我怎样才能达到关于结果

我从下面的代码中得到周数

Calendar c = Calendar.getInstance();
c.set(Calendar.DAY_OF_MONTH, 6);
c.set(Calendar.MONTH, 1);
c.set(Calendar.YEAR, 2013);

int weekNo = c.get(Calendar.WEEK_OF_YEAR);
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3 回答 3

2

试试这个……我已经对 Achintya Jha 代码进行了编辑并添加了更多更改……工作得很好，感谢 Achintya Jha

Calendar c = Calendar.getInstance();
c.set(Calendar.DAY_OF_MONTH, 14);
c.set(Calendar.MONTH, 1);
c.set(Calendar.YEAR, 2013);

int weekNo = c.get(Calendar.WEEK_OF_YEAR);

//Set the Week No
c.set(Calendar.WEEK_OF_YEAR, weekNo);

c.clear();

//Set the Week Year and the Week No
c.set(Calendar.WEEK_OF_YEAR, weekNo);
c.set(Calendar.YEAR, 2013);


SimpleDateFormat formatter = new SimpleDateFormat("EEE dd/MM/yyyy"); // PST`
//Get Week Start Date 
Date startDate = c.getTime();
//Now it will be sunday so add plus one so now it becomes Monday
c.add(Calendar.DATE, 1);
for (int i = 0; i < 5; i++) {
    //From Monday to Friday Dates will be Printed
    System.out.println(formatter.format(c.getTime()));
    c.add(Calendar.DATE, 1);
}
于 2013-02-11T10:50:41.530 回答
1

从 2013 年 6 月 2 日起：

        GregorianCalendar c = new GregorianCalendar(2013, 1, 6);
        c.add(Calendar.DAY_OF_YEAR, Calendar.MONDAY - c.get(Calendar.DAY_OF_WEEK));
        DateFormat df = new SimpleDateFormat("d-M-yyyy");
        while(c.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY) {
            if (c.get(Calendar.YEAR) == 2013) {
                System.out.printf("%-10tA%10s%n", c.getTime(), df.format(c.getTime()));
            }
            c.add(Calendar.DAY_OF_YEAR, 1);
        }
prints

    Monday      4-2-2013
    Tuesday     5-2-2013
    Wednesday   6-2-2013
    Thursday    7-2-2013
    Friday      8-2-2013
from week 6 of 2013:

    GregorianCalendar c = new GregorianCalendar(2013, 0, 1);
    c.add(Calendar.WEEK_OF_YEAR, 6 - 1);
    c.add(Calendar.DAY_OF_YEAR, Calendar.MONDAY - c.get(Calendar.DAY_OF_WEEK));
        DateFormat df = new SimpleDateFormat("d-M-yyyy");
        while(c.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY) {
            if (c.get(Calendar.YEAR) == 2013) {
                System.out.printf("%-10tA%10s%n", c.getTime(), df.format(c.getTime()));
            }
            c.add(Calendar.DAY_OF_YEAR, 1);
        }

印刷

Monday      4-2-2013
Tuesday     5-2-2013
Wednesday   6-2-2013
Thursday    7-2-2013
Friday      8-2-2013
于 2013-02-11T10:49:18.873 回答
0 
public static void main(String[] args) {
    getWeekOfDates(2013, 2, 11);

}

private static void getWeekOfDates(int year, int month, int day) {

    Calendar c = Calendar.getInstance();
    c.set(Calendar.YEAR, year);
    c.set(Calendar.MONTH, month);
    int weekOfMonth = c.get(Calendar.WEEK_OF_MONTH);
    c.set(Calendar.WEEK_OF_MONTH, weekOfMonth);

    DateFormat df = new SimpleDateFormat("EEE dd-MM-yyyy");
    for (int i = 0; i < 5; i++) {
        System.out.println(df.format(c.getTime()));
        c.add(Calendar.DATE, 1);
    }

}

试试这个：我根据您的要求进行了编辑。

输出：

Mon 11-03-2013
Tue 12-03-2013
Wed 13-03-2013
Thu 14-03-2013
Fri 15-03-2013
于 2013-02-11T09:26:16.223 回答