0

我有一个包含这些列的表：

id | series_id | season_id | episode_id |  title | type ...

我想获得具有唯一series_id位置season_id和episode_id最大值的行。

4

4 回答 4

1

一种解决方案是这样做：

SELECT t1.*
FROM YourTable AS t1
INNER JOIN 
(
   SELECT 
     series_id, 
     MAX(season_id)  AS MAxSeasonId, 
     MAX(Episode_id) AS MAXEpisodeID
   FROM yourTable 
   GROUP BY series_id
) AS t2  ON t1.series_id  = t2.series_id
        AND t1.season_id  = t2.MaxSeasonId
        AND t1.episode_id = t2.MaxEpisode_id;
于 2013-02-10T09:28:08.263 回答
0

我认为这可能有点矫枉过正，但这是我发现对我有用的唯一方法。

DECLARE @SeriesInfo TABLE
(
    id          INT,
    series_id   INT,
    season_id   INT,
    episode_id  INT,
    title       VARCHAR(50),
    type        CHAR(1)
);
INSERT INTO @SeriesInfo VALUES ( 1, 1, 1, 1, 'Series 1 Season 1 Episode 1', 'A'),
                               ( 2, 1, 1, 2, 'Series 1 Season 1 Episode 2', 'A'),
                               ( 3, 1, 1, 3, 'Series 1 Season 1 Episode 3', 'A'),
                               ( 4, 1, 2, 1, 'Series 1 Season 2 Episode 1', 'A'),
                               ( 5, 1, 2, 2, 'Series 1 Season 2 Episode 2', 'A'),
                               ( 6, 2, 1, 1, 'Series 2 Season 1 Episode 1', 'A'),
                               ( 7, 2, 1, 2, 'Series 2 Season 1 Episode 2', 'A'),
                               ( 8, 2, 1, 3, 'Series 2 Season 1 Episode 3', 'A'),
                               ( 9, 2, 1, 4, 'Series 2 Season 1 Episode 4', 'A'),
                               (10, 2, 2, 1, 'Series 2 Season 2 Episode 1', 'A'),
                               (11, 2, 2, 2, 'Series 2 Season 2 Episode 2', 'A'),
                               (12, 2, 2, 3, 'Series 2 Season 2 Episode 3', 'A');
SELECT  id,
        series_id,
        season_id,
        episode_id,
        title,
        type
FROM    (
         SELECT ROW_NUMBER() OVER(PARTITION BY series_id ORDER BY season_id DESC, episode_id DESC) RowNum,
                *
         FROM   @SeriesInfo
        )   X
WHERE   X.RowNum = 1;

--SELECT ROW_NUMBER() OVER(PARTITION BY series_id ORDER BY season_id DESC, episode_id DESC) RowNum, * FROM @SeriesInfo;

（样本数据过多见谅）

关键是，如果我们只取 series_id 和 season_id 的最大值，我们将不会得到任何一个系列的有效配对。在这两种情况下，第 1 季的剧集都比第 2 季多。ROW_NUMBER() 子句将每行返回一个唯一编号，但由于“PARTITION BY”，它将为每个 series_id 重新启动（参见注释掉的行）。如果我们只返回 ROW_NUMBER 为 1 的行，我们将得到每个 series_id 的一行，它将是 max season_id 中具有最大 episode_id 的行。

于 2013-08-23T19:47:19.710 回答
0

尝试这个..

SELECT * FROM TABLE
HAVING MAX(season_id) AND MAX(episode_id)
GROUP BY series_id

:)

于 2013-02-11T02:17:17.220 回答
0 
SELECT *
FROM TableName t1
WHERE EXISTS (
              SELECT 1
              FROM t2
              WHERE t1.series_id = t2.series_id
              HAVING MAX(t2.season_id) = t1.season_id
                AND MAX(t2.episode_id ) = t1.episode_id
              )
于 2013-02-10T11:10:09.110 回答