-1

我有一个这种格式的 URL "http://testserver.com/Test/login!checkUser.cc?email=testemail123@gmail.com"。我想把它发送到服务器,然后我会得到 Json 格式的响应"[{"status":"0"}]"。如何在android中实现这一点。

4

1 回答 1

1

您将使用 anHttpClient和其他Http*类。

HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://testserver.com/Test/login!checkUser.cc?email=testemail123@gmail.com");
HttpResponse response = client.execute(request);

// Check if server response is valid
StatusLine status = response.getStatusLine();
if (status.getStatusCode() != 200) {
   throw new IOException("Invalid response from server [" + status.toString() + "]");
                    }

// Pull content stream from response
HttpEntity entity = response.getEntity();
InputStream inputStream = entity.getContent();

StringBuilder builder = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
String line;
while ((line = reader.readLine()) != null) {
   builder.append(line);
                    }

//return result from buffered stream
String dataAsString = builder.toString();
JSONObject jsonObject = new JSONObject(dataAsString);
于 2013-02-10T05:39:15.243 回答