ruby - 检查数组是否包含字符串，不区分大小写

Question

我正在尝试编写一个从单词列表中删除单词的应用程序：

puts "Words:"
text = gets.chomp
puts "Words to remove:"
remove = gets.chomp
words = text.split(" ")
removes = remove.split(" ")
words.each do |x| 
    if removes.include.upcase? x.upcase
        print "REMOVED "
    else
        print x, " "
    end
end

我如何使这种情况不敏感？我试着放在.upcase那里，但没有运气。

Answer 1

words.each do |x| 
    if removes.select{|i| i.downcase == x.downcase} != []
        print "REMOVED "
    else
        print x, " "
    end
end

array#select如果块为真，将从数组中选择任何元素。因此，如果select不选择任何元素并返回一个空数组，则它不在数组中。

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编辑

您也可以使用if removes.index{|i| i.downcase==x.downcase}. 它比它执行得更好，select因为它不创建临时数组并在找到第一个匹配项时返回。

Answer 2

puts "Words:"
text = gets.chomp
puts "Words to remove:"
remove = gets.chomp
words = text.split(" ")
removes = remove.upcase.split(" ")

words.each do |x|
  if removes.include? x.upcase
    print "REMOVED "
  else
    print x, " "
  end
end