更新
好像当我从这个问题中复制字符串" AAAAAA"
并替换它时。该程序正常工作。
所以我只是通过改回" AAAAAA"
我以前的错误字符串来做一些测试。然后删除所有空格并通过键入手动输入它,它可以工作!?!?。
这是我的完整代码
public static void main(String[] args) {
URL url;
InputStream is = null;
try {
url = new URL(
"http://writer.dek-d.com/nattione/story/viewlongc.php?id=466201&chapter=966");
is = url.openStream(); // throws an IOException
String result = convertStreamToString(is);
createFictionFiles(result);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
// nothing to see here
}
}
}
public static void createFictionFiles(String html) {
Document doc = Jsoup.parse(html);
Element title = doc.select("title").first();
Element table = doc.select("#story_body").first();
String showTitle = "";
String showStory = "";
BufferedWriter bw;
try {
showTitle = new String(title.text());
showStory = new String(table.text());
//showStory = " AAAAAA"; these spaces I copy it from log in eclipse. It is the spaces that come from web
boolean find = showStory.contains("\\t");
boolean find1 = showStory.contains("\\n");
boolean find2 = showStory.contains("\\x0b");
boolean find3 = showStory.contains("\\r");
boolean find4 = showStory.contains("\\f");
boolean find5 = showStory.contains(" ");
boolean find6 = showStory.contains(" ");
boolean find7 = showStory.matches("\\s");
System.out.println("\\t = " + find);
System.out.println("\\n = " + find1);
System.out.println("\\x0b = " + find2);
System.out.println("\\r = " + find3);
System.out.println("\\f = " + find4);
System.out.println(" = " + find5);
System.out.println(" = " + find6);
System.out.println("\\s = " + find7);
File file = new File("D:/" + "test"
+ ".txt");
if (!file.exists()) {
file.createNewFile();
}
FileWriter fw = new FileWriter(file.getAbsoluteFile());
bw = new BufferedWriter(fw);
bw.write(showStory);
bw.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static String convertStreamToString(InputStream is) {
Scanner s = new Scanner(is, "TIS-620").useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
老的
我有这个字符串
showStory = " AAAAAA";
这些字符串是从 Web 检索并使用库将其解析为字符串格式
我想将超过 3 英寸的空间分开,将它们替换为"\n"
我有这些测试。
boolean find = showStory.contains("\\t");
boolean find1 = showStory.contains("\\n");
boolean find2 = showStory.contains("\\x0b");
boolean find3 = showStory.contains("\\r");
boolean find4 = showStory.contains("\\f");
boolean find5 = showStory.contains(" ");
boolean find6 = showStory.contains(" ");
boolean find7 = showStory.contains("\\s");
结果是
\t = false
\n = false
\x0b = false
\r = false
\f = false
= true
= false
\s = false
我不知道为什么在我的字符串中有 8 个空格的情况下,为什么会有多个空格给我 false。我也将方法从更改为contains
,matches
但所有结果都是错误的。
谁能帮我这个?
谢谢。