我创建了一个名为 e 的链表。我使用复制构造函数来创建 e2，但由于某种原因，当我尝试打印 e2 时程序总是崩溃。有人可以向我解释并帮我解决这个问题，谢谢。
#include <iostream>
#include <ctime>
#include <cmath>
using namespace std;
class Element
{
public: Element();//constructor
Element(const Element&); //copy constructor
//Element& Element::operator =(const Element & from);
void Addelement(int row, int col, int value);
void swap(int num,int x, int arr[100]);
void printelement();
void rowordermajor();
private:
typedef Element* ElementPtr;
int row;
int col;
int value;
ElementPtr next;
ElementPtr head;
bool comparegreater(ElementPtr temp1, ElementPtr temp2);
};
int main()
{
Element e;
for (int i=0;i<5;i++)
{
e.Addelement(i,i,i);
}
e.printelement();
Element e2(e);
//e2.printelement();
system("PAUSE");
}
Element::Element()//normal constructor
{
head=NULL;
}
Element::Element(const Element& e)
{
this->row=e.row;
this->col=e.col;
this->value=e.value;
this->next=e.next;
}
void Element::Addelement(int row, int col, int value )
{
ElementPtr temp= new Element;
temp->row=row;
temp->col=col;
temp->value=value;
temp->next=head;
head=temp;
}
void Element::printelement()//why does it print backwards
{
ElementPtr temp=head;
while (temp != NULL)
{
cout<<"( "
<<temp->row
<<" , "
<<temp->col
<<" , "
<<temp->value
<<" ) ";
cout<<endl;
temp=temp->next;
}
}