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我是 C# 和 Windows 窗体应用程序的新手。现在，我想在我的表单中创建一个 Datagridview，我想用业务对象的属性填充其行。我遵循了这个 msdn 页面中的示例：如何：将对象绑定到 Windows 窗体 DataGridView 控件并创建了我自己的程序，但我没有得到与 msdn 示例中类似的结果，而是得到了一个包含三个空行的 datagridview。我究竟做错了什么？这是我的程序：

using System;
using System.Windows.Forms;


public class Form3 : Form
{
    private DataGridView dataGridView1 = new DataGridView();
    private BindingSource bindingSource1 = new BindingSource();

    public Form3()
    {            
        this.Load += new System.EventHandler(EnumsAndComboBox_Load);
    }

    private void EnumsAndComboBox_Load(object sender, System.EventArgs e)
    {
        // Populate the data source.           
        bindingSource1.Add(new Test("bli", "bla", "blop", "ha", "ho", "he"));
        bindingSource1.Add(new Test("bli", "bla", "blop", "ha", "ho", "he"));

        // Initialize the DataGridView.
        dataGridView1.AutoGenerateColumns = false;
        dataGridView1.AutoSize = true;
        dataGridView1.DataSource = bindingSource1;

        // Initialize and add a text box column.
        DataGridViewColumn column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name1";
        column.Name = "Name1";
        dataGridView1.Columns.Add(column);

        // Initialize and add a check box column.
        column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name2";
        column.Name = "Name2";
        dataGridView1.Columns.Add(column);

        column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name3";
        column.Name = "Name3";
        dataGridView1.Columns.Add(column);

        column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name4";
        column.Name = "Name4";
        dataGridView1.Columns.Add(column);

        column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name5";
        column.Name = "Name5";
        dataGridView1.Columns.Add(column);

        column = new DataGridViewTextBoxColumn();
        column.DataPropertyName = "Name6";
        column.Name = "Name6";
        dataGridView1.Columns.Add(column);

        // Initialize the form.
        this.Controls.Add(dataGridView1);
        this.AutoSize = true;
        this.Text = "DataGridView object binding demo";
    }

    #region "test object"
    private class Test
    {
        private string test1;
        private string test2;
        private string test3;
        private string test4;
        private string test5;
        private string test6;

        public Test(string s1, string s2, string s3, string s4, string s5, string s6)
        {
            test1 = s1;
            test2 = s2;
            test3 = s3;
            test4 = s4;
            test5 = s5;
            test6 = s6;
        }

        public Test()
        {
            test1 = "bla";
            test2 = "bla";
            test3 = "bla";
            test4 = "bla";
            test5 = "bla";
            test6 = "bla";
        }


        public string Test1
        {
            get
            {
                return test1;
            }
            set
            {
                test1 = value;
            }
        }

        public string Test2
        {
            get
            {
                return test2;
            }
            set
            {
                test2 = value;
            }
        }

        public string Test3
        {
            get
            {
                return test3;
            }
            set
            {
                test3 = value;
            }
        }

        public string Test4
        {
            get
            {
                return test4;
            }
            set
            {
                test4 = value;
            }
        }

        public string Test5
        {
            get
            {
                return test5;
            }
            set
            {
                test5 = value;
            }
        }

        public string Test6
        {
            get
            {
                return test6;
            }
            set
            {
                test6 = value;
            }
        }
    }

    #endregion

    static class Program
    {
        [STAThread]
        public static void Main()
        {
            Application.Run(new Form3());
        }
    }
}
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3 回答 3

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您正在将列绑定到Name从 1 到 6 调用的属性，但在您的对象中没有这样的属性。更改Name为Test。IE

由此：

column = new DataGridViewTextBoxColumn();
column.DataPropertyName = "Name6";
column.Name = "Name6";
dataGridView1.Columns.Add(column);

对此：

column = new DataGridViewTextBoxColumn();
column.DataPropertyName = "Test6";
column.Name = "Name6";
dataGridView1.Columns.Add(column);

也正如@noobob 所建议的那样，移动你的

dataGridView1.DataSource = bindingSource1;

到方法结束

于 2013-02-08T14:39:01.797 回答
1

每列的“DataPropertyName”属性必须与正在评估的数据对象的属性名称匹配。因此，如果您只进行这样的微小更改：

column.DataPropertyName = "Test1";

一切都应该工作。

于 2013-02-08T14:41:35.607 回答
0

column.DataPropertyName应该设置为您在数据源类中指定的属性名称。尝试这个 ：

    column = new DataGridViewTextBoxColumn();
    column.DataPropertyName = "Test1";
    column.Name = "Test1";
    dataGridView1.Columns.Add(column);

    column = new DataGridViewTextBoxColumn();
    column.DataPropertyName = "Test2";
    column.Name = "Test2";
    dataGridView1.Columns.Add(column);

    column = new DataGridViewTextBoxColumn();
    column.DataPropertyName = "Test3";
    column.Name = "Test3";
    dataGridView1.Columns.Add(column);
于 2013-02-08T14:44:27.477 回答