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<?php 
// This block grabs the whole list for viewing
include "storescripts/connect_to_mysql.php";
$cat=$_POST['cat'];
$sql = mysql_query("select * from categories,products_cat,products where categories.id=products_cat.cat_id and products.id=products_cat.prod_id and categories=$cat");
$catCount = mysql_num_rows($sql); // count the output amount
    while($row = mysql_fetch_array($sql)){ 
             $id = $row["id"];
             $product_name = $row["product_name"];
             $price = $row["price"];
             $date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
             $prod_list .= "category ID: $id - <strong>$product_name</strong> <br />";
    }

?>

我有这三个表：1）产品表：id，product_name，price，category，subcategory

2) 类别表：id,cat

3）products_cat表：cat_id、prod_id

我无法显示用户将从命令行输入的特定类别的产品 cat=x ，它只会给我这个错误：

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/perzul12/public_html/beta/show.php on line 6

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/perzul12/public_html/beta/show.php on line 7

请帮我 ！这是我这个月唯一的金钱来源，我做不到！

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1 回答 1

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这里的工作不在已弃用的mysql_功能中。相反，您没有返回有效的结果集。尝试这个。

"select products_cat.products, categories.* 
from categories,
left join products_cat on products_cat.cat_id=products.id
where categories={$cat}"
于 2013-02-08T13:30:28.103 回答