1

我需要这个 Spring 测试项目的帮助。我有一个带有安全检查的简单登录页面，Spring 检测良好或床登录但在重定向到登录成功页面或登录失败页面时给出 404 Page not fount 错误。

配置是

应用背景 

    <!--
    Most controllers will use the ControllerClassNameHandlerMapping above, but
    for the index controller we are using ParameterizableViewController, so we must
    define an explicit mapping for it.
    -->
    <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="login.htm">LoginController</prop>
            </props>
        </property>
    </bean>

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/WEB-INF/jsp/"
          p:suffix=".jsp" />

    <!--
    The index controller.
    -->
    <bean name="LoginController"
          class="org.springframework.web.servlet.mvc.ParameterizableViewController"
          p:viewName="login" />

</beans>

安全

    <http auto-config="true">
        <intercept-url pattern="/welcome*" access="ROLE_USER" />
        <form-login login-page="/login" default-target-url="/welcome"
            authentication-failure-url="/loginfailed" />
        <logout logout-success-url="/logout" />
    </http>

    <authentication-manager>
      <authentication-provider>
        <user-service>
            <user name="mkyong" password="123456" authorities="ROLE_USER" />
        </user-service>
      </authentication-provider>
    </authentication-manager>

</beans:beans>

WEB.XML

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>2</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>*.htm</url-pattern>
</servlet-mapping>

<context-param>
    <param-name>contextConfigLocation</param-name>
<param-value>
        /WEB-INF/dispatcher-servlet.xml,
        /WEB-INF/spring-security.xml 
</param-value>
</context-param>

<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>

<welcome-file-list>
    <welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>

<!-- Spring Security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

登录控制器是

@Controller

公共类登录控制器 {

@RequestMapping(value="/welcome", method = RequestMethod.GET)
public String printWelcome(ModelMap model, Principal principal ) {

    String name = principal.getName();
    model.addAttribute("username", name);
    model.addAttribute("message", "Spring Security Custom Form example");
    return "hello";

}

@RequestMapping(value="/login", method = RequestMethod.GET)
public String login(ModelMap model) {

    return "login";

}

@RequestMapping(value="/loginfailed", method = RequestMethod.GET)
public String loginerror(ModelMap model) {

    model.addAttribute("error", "true");
    return "login";

}

@RequestMapping(value="/logout", method = RequestMethod.GET)
public String logout(ModelMap model) {

    return "login";

}

}

错误在哪里？传统知识。

4

0 回答 0