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我不知道我的登录页面有什么问题。我登录后它仍然在登录页面中。

我有一个餐桌工作人员

CREATE TABLE `staff` (                    
          `staffid` varchar(25) NOT NULL,         
          `password` varchar(25) DEFAULT NULL,    
          `staffname` varchar(50) DEFAULT NULL,   
          `staffemail` varchar(50) DEFAULT NULL,  
          `level` int(2) DEFAULT NULL,            
          PRIMARY KEY (`staffid`)                 
        ) ENGINE=InnoDB DEFAULT CHARSET=latin1

有两个级别。1 为员工 2 为管理员 输入员工 ID 和密码后，页面应根据其级别转到页面。

1.登录.php

<? session_start(); ?>
<title>Inventory Management System</title>
<center>
 <form name="form1" method="POST" action="logincheck.php">
    <table width="468" height="328" border="0">
      <tr>
        <td height="124" colspan="2">
        <?php include "header.php"?></td>
      </tr>
      <tr>
        <td width="184" height="65" 
        align = "right">No Kakitangan</td>
        <td width="274"><label for="staffid"></label>
        <input type="text" name="staffid" id="staffid"></td>
      </tr>
      <tr>
        <td width="184" height="60" 
        align = "right">Kata Laluan</td>
        <td><label for="password"></label>
        <input type="password" name="password" id="password"></td>
      </tr>
      <tr>
        <td height="42" colspan="2" 
        align = "center"><input type="submit" name="button" id="button" value="Log In">
        <input type="reset" name="button2" id="button2" value="Batal"></td>
      </tr>
   </table>
    <p>
      <input type="hidden" name="MM_insert" value="form1"/>
    </p>

  </form>
</center>

2.logincheck.php

<?php require_once('Connections/sqlconnection.php'); ?>
<? session_start(); ?>
<?php
    $staffid = isset($_POST['staffid']) ? $_POST['staffid'] : "";
    $password = isset($_POST['password']) ? $_POST['password'] : "";
    //get user info from the database base on staffid and password
    mysql_select_db($database_sqlconnection, $sqlconnection);
    $sql = "select s.* from staff s where s.staffid = '".$staffid."' and
    s.password = '".$password."'" ;
    $result1 = mysql_query($sql,$sqlconnection) or die(mysql_error());
    $rowUsr = mysql_fetch_array($result1);
    $cnt = mysql_num_rows($result1);
    $level = '';
    //if staffid exists
    if($cnt > 0)
    {
        $_SESSION['staffid']=$staffid;
        $level = $rowUsr['level'];
        //compare the password
        if ($level == 1)
             $_SESSION['userlevel']='staff';
        else if ($level == 2)
                  $_SESSION['userlevel']='admin';
        else $_SESSION['userlevel']='err';
             echo "<script> location.href='index.php'; </script>";
    }
    else {
          echo "<script> alert('Sila masukkan semula. No Kakitangan atau Kata Laluan salah.');</script>";
    echo "<script> location.href='login.php'; </script>";
    }
    mysql_free_result($result1);
?>
4

1 回答 1

0

您需要使用mysql_data_seek将内部结果指针移到开头。尝试使用：

mysql_data_seek($result1, 0);

利用：

$rowUsr = mysql_fetch_array($result1);
mysql_data_seek($result1, 0);
$cnt = mysql_num_rows($result1);

发生的情况是，一旦您这样做，指针就会留在数据集的末尾mysql_fetch_array。mysql_data_seek($result1, 0);将它返回到开头。

于 2013-02-08T02:29:03.053 回答