由于我查询的性质，我有计数为 3 的记录，这些记录也符合计数为 2 的条件，依此类推。我想知道是否可以查询“计数大于 x 且小于 7”？我怎么会写这个。这是我当前的代码。
GROUP BY meetingID
HAVING COUNT( caseID )<4
我想要类似的东西
GROUP BY meetingID
HAVING COUNT( caseID )<4 AND >2
这样它就只能算到 3
问问题
142292 次
6 回答
91
GROUP BY meetingID
HAVING COUNT(caseID) < 4 AND COUNT(caseID) > 2
于 2013-02-07T16:39:18.577 回答
11
不需要做两次检查，为什么不检查count = 3：
GROUP BY meetingID
HAVING COUNT(caseID) = 3
如果要使用多项检查，则可以使用：
GROUP BY meetingID
HAVING COUNT(caseID) > 2
AND COUNT(caseID) < 4
于 2013-02-07T16:39:39.797 回答
4
对于您的示例查询，大于 2 且小于 4 的唯一可能值是 3，因此我们简化：
GROUP BY meetingID
HAVING COUNT(caseID) = 3
在您的一般情况下：
GROUP BY meetingID
HAVING COUNT(caseID) > x AND COUNT(caseID) < 7
或者（可能更容易阅读？），
GROUP BY meetingID
HAVING COUNT(caseID) BETWEEN x+1 AND 6
于 2013-02-07T16:39:32.233 回答
3
在这里，我正在编写完整的查询，这将消除您的所有疑问
SELECT BillingDate,
COUNT(*) AS BillingQty,
SUM(BillingTotal) AS BillingSum
FROM Billings
WHERE BillingDate BETWEEN '2002-05-01' AND '2002-05-31'
GROUP BY BillingDate
HAVING COUNT(*) > 1
AND SUM(BillingTotal) > 100
ORDER BY BillingDate DESC
于 2014-09-02T08:04:12.133 回答
2
像这样的东西？
HAVING COUNT(caseID) > 2
AND COUNT(caseID) < 4
于 2013-02-07T16:41:49.123 回答
-1
select CUSTOMER_CODE,nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) DEBIT,nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) CREDIT,
nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) BALANCE from TRANSACTION
GROUP BY CUSTOMER_CODE
having nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) > 0
AND (nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0))) > 0
于 2014-03-11T06:42:53.760 回答