android - 如何从 android 以 JSON 格式发布数据？

Question

在Android中进行JSON解析，因为我想在http URL上发布以下格式的数据，

 webdata={"email":"test@test.com","password":"123456"}  

我如何在 http url 上使用 httppost 为这个 JSON 发布这些数据？

Answer 1

首先，您可以准备您的 json 格式数据，然后根据您的要求将其作为您的请求发送 GET 或 POST 这需要使用 Asynctask 完成

JSONObject jObject = new JSONObject();
try{
jObject.put("email",urvalue);
jObject.put("password",urvalue);

List<NameValuePair> pairs = new ArrayList<NameValuePair>();
pairs.add(new BasicNameValuePair("webdata", jObject.toString()));

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(pairs, "UTF-8"));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();

}catch(Exception e){}

Answer 2

使用以下方法生成 json 对象

private JSONObject getConvertedinJson(String email, String password) {

    JSONObject object = new JSONObject();
    try {
        object.put("email", email);
        object.put("password", password);
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return object;
}

之后使用以下方法在 url 上发布 json 对象

    public JSONObject getJSONFromUrl(String url, JSONObject jObj) {

    // Making HTTP request
    try {
        // Default Http Client
        DefaultHttpClient httpClient = new DefaultHttpClient();
        // Http Post Header
        HttpPost httpPost = new HttpPost(url);
        StringEntity se = new StringEntity(jObj.toString());
        httpPost.setEntity(se);
        httpPost.setHeader("Accept", "application/json");
        httpPost.setHeader("Content-type", "application/json");
        // Execute Http Post Request
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    /*
     * To convert the InputStream to String we use the
     * BufferedReader.readLine() method. We iterate until the BufferedReader
     * return null which means there's no more data to read. Each line will
     * appended to a StringBuilder and returned as String.
     */
    try {
        // Getting Server Response
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        // Reading Server Response
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    Log.e("JSON Parser", jObj.toString());
    return jObj;

}

现在使用以下语句获取 json 响应。

JSONObject jsonObject = getJSONFromUrl(
                "www.url.com/api",
                getConvertedinJson("test@test.com",
                        "123456"));

现在您可以根据需要轻松反序列化 jsonObject。

注意：您的帖子数据必须是 Json 对象。正如我所见 webdata={"email":"test@test.com","password":"123456"} 不是 jsonObject 这里 json Object 只是 {"email":"test@test.com","password ":"123456"}

Answer 3

使用StringEntity类。

StringEntity entity = new StringEntity("Your JSON String",HTTP.UTF_8);

然后将其添加到您的HttpPost

httpPost.setEntity(entity);