3

我想在按钮单击事件上执行：

localhost/codeigniter/controller/method

该方法将从网页中提取关键字并将其存储在数据库中。其中有多个子方法也应该在后台运行。我不想让用户在此期间等待。我读了这个。这对我有用吗？任何其他拯救生命的建议都是最受欢迎的。

4

2 回答 2

1

基于这个线程，我为我的 codeigniter 项目做了这个。它工作得很好。您可以在后台处理任何功能。

一个接受异步调用的控制器。

class Daemon extends CI_Controller
{
    // Remember to disable CI's csrf-checks for this controller

    function index( )
    {
        ignore_user_abort( 1 );
        try
        {
            if ( strcmp( $_SERVER['REMOTE_ADDR'], $_SERVER['SERVER_ADDR'] ) != 0 && !in_array( $_SERVER['REMOTE_ADDR'], $this->config->item( 'proxy_ips' ) ) )
            {
                log_message( "error", "Daemon called from untrusted IP-address: " . $_SERVER['REMOTE_ADDR'] );
                show_404( '/daemon' );
                return;
            }

            $this->load->library( 'encrypt' );
            $params = unserialize( urldecode( $this->encrypt->decode( $_POST['data'] ) ) );
            unset( $_POST );
            $model = array_shift( $params );
            $method = array_shift( $params );
            $this->load->model( $model );
            if ( call_user_func_array( array( $this->$model, $method ), $params ) === FALSE )
            {
                log_message( "error", "Daemon could not call: " . $model . "::" . $method . "()" );
            }
        }
        catch(Exception $e)
        {
            log_message( "error", "Daemon has error: " . $e->getMessage( ) . $e->getFile( ) . $e->getLine( ) );
        }
    }
}

还有一个执行异步调用的库

class Daemon
{
    public function execute_background( /* model, method, params */ )
    {
        $ci = &get_instance( );
        // The callback URL (its ourselves)
        $parts = parse_url( $ci->config->item( 'base_url' ) . "/daemon" );
        if ( strcmp( $parts['scheme'], 'https' ) == 0 )
        {
            $port = 443;
            $host = "ssl://" . $parts['host'];
        }
        else 
        {
            $port = 80;
            $host = $parts['host'];
        }
        if ( ( $fp = fsockopen( $host, isset( $parts['port'] ) ? $parts['port'] : $port, $errno, $errstr, 30 ) ) === FALSE )
        {
            throw new Exception( "Internal server error: background process could not be started" );
        }
        $ci->load->library( 'encrypt' );
        $post_string = "data=" . urlencode( $ci->encrypt->encode( serialize( func_get_args( ) ) ) );
        $out = "POST " . $parts['path'] . " HTTP/1.1\r\n";
        $out .= "Host: " . $host . "\r\n";
        $out .= "Content-Type: application/x-www-form-urlencoded\r\n";
        $out .= "Content-Length: " . strlen( $post_string ) . "\r\n";
        $out .= "Connection: Close\r\n\r\n";
        $out .= $post_string;
        fwrite( $fp, $out );
        fclose( $fp );
    }
}

可以调用此方法来处理“背景”中的任何 model::method()。它使用可变参数。

$this->load->library('daemon');
$this->daemon->execute_background( 'model', 'method', $arg1, $arg2, ... );
于 2013-02-08T00:13:23.473 回答
0

您可以在套接字中编写：

$fp = fsockopen($_SERVER['HTTP_HOST'], 80, $errno, $errstr, 30);
$data = http_build_query($params, '', '&'); //$params - array with POST data
fwrite($fp, "POST " . ('/controller/action') . " HTTP/1.1\r\n");
fwrite($fp, "Host: ".$_SERVER['HTTP_HOST']."\r\n");
fwrite($fp, "Content-Type: application/x-www-form-urlencoded\r\n");
fwrite($fp, "Content-Length: " . strlen($data) . "\r\n");
fwrite($fp, "Connection: Close\r\n\r\n");
fwrite($fp, $data);
fclose($fp);
于 2013-02-07T12:12:13.163 回答