5

我正在尝试使用表达式树创建动态查询以匹配以下语句：

var items = data.Where(i => i.CoverageType == 2).Select(i => i.LimitSelected);

我可以创建 where 方法并从中获得结果；但是，我无法创建 select 方法。

这是我的 where 方法：

var parm = Expression.Parameter(typeof(BaseClassData), "baseCoverage");

var queryData = data.AsQueryable();

var left = Expression.Property(parm, "CoverageType");
var right = Expression.Constant(2m);
var e1 = Expression.Equal(left, right);

var whereMethod = Expression.Call(
    typeof(Queryable), 
    "Where", 
    new Type[] { queryData.ElementType }, 
    queryData.Expression, 
    Expression.Lambda<Func<BaseClassData, bool>>(e1, new ParameterExpression[] { parm }));

这就是我用于 select 方法的内容：

var selectParm = Expression.Property(parm, "LimitSelected");
     var selectMethod = Expression.Call(
        typeof(Enumerable),
        "Select",
        new Type[]{typeof(BaseClassData), typeof(decimal)},
        whereMethod,
        Expression.Lambda<Func<BaseClassData, decimal>>(selectParm, new ParameterExpression[]{ parm})

        );

当我运行代码时，我收到此错误：

类型“System.Linq.Enumerable”上没有通用方法“Select”与提供的类型参数和参数兼容。如果方法是非泛型的，则不应提供类型参数。

我也尝试将 Enumerable 更改为 Queryable 并且我得到了同样的错误。

4

2 回答 2

4

无需使用Expression.Call，可以直接构造Expression Tree；我创建了一个静态方法来帮助我生成动态查询：

public static void Test(string[] args) {
  using (var db = new DBContext()) {
    //query 1
    var query1 = db.PrizeTypes.Where(m => m.rewards == 1000).Select(t => t.name);

    //query 2 which equal to query 1
    Expression<Func<PrizeType, bool>> predicate1 = m => m.rewards == 1000;
    Expression<Func<PrizeType, string>> selector1 = t => t.name;
    var query2 = db.PrizeTypes.Where(predicate1).Select(selector1);
    Console.WriteLine(predicate1);
    Console.WriteLine(selector1);
    Console.WriteLine();

    //query 3 which equal to query 1 and 2
    Expression<Func<PrizeType, bool>> predicate2 = GetPredicateEqual<PrizeType>("rewards", (Int16)1000);
    Expression<Func<PrizeType, string>> selector2 = GetSelector<PrizeType, string>("name");
    var query3 = db.PrizeTypes.Where(predicate2).Select(selector2);
    Console.WriteLine(predicate2);
    Console.WriteLine(selector2);

    //as you can see, query 1 will equal query 2 equal query 3
  }
}

public static Expression<Func<TEntity, bool>> GetPredicateEqual<TEntity>(string fieldName, object fieldValue) where TEntity : class {
  ParameterExpression m = Expression.Parameter(typeof(TEntity), "t");
  var p = m.Type.GetProperty(fieldName);
  BinaryExpression body = Expression.Equal(
    Expression.Property(m, fieldName),
    Expression.Constant(fieldValue, p.PropertyType)
  );
  return Expression.Lambda<Func<TEntity, bool>>(body, m);
}

public static Expression<Func<T, TReturn>> GetSelector<T, TReturn>(string fieldName)
  where T : class
  where TReturn : class {
  var t = typeof(TReturn);
  ParameterExpression p = Expression.Parameter(typeof(T), "t");
  var body = Expression.Property(p, fieldName);
  return Expression.Lambda<Func<T, TReturn>>(body, new ParameterExpression[] { p });
}
于 2013-03-04T11:05:46.623 回答
-1

This might help with the error you describe above.

You don't need to create your own where/select however, the ones built into c#/linq work just fine with your own classes:

void Main()
{
    List<testdata> data = new List<testdata>();
    Directory.GetFiles(@"C:\").ToList().ForEach(x=>data.Add(new testdata(){file=x,returnable=1}));
    data.Where(x=>x.file.Contains("g")).Select(x=>x.file).Dump();
}

class testdata
{
    public string file {get; set;}
    public string returnable {get; set;}
}
于 2013-03-01T11:32:53.587 回答