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我已经提供了带有模式和示例数据的 sql fiddle。

http://sqlfiddle.com/#!2/e9d22/7/0

如果我想知道泰国有多少个省和多少个城市。

Country Name | No. Provinces | No. Cities
  Thailand   |   77          |  1234

我猜它需要使用多个 COUNT(*) 但我不知道如何使用它。

有人知道请提出解决方案吗?

4

3 回答 3

1

您需要使用GROUP BYCOUNT

SELECT c.name, count(distinct p.id) provincecoutn, count(distinct city.id) citycount
FROM country c
  LEFT JOIN province p on c.id = p.country_id
  LEFT JOIN City on p.id = city.province_id
GROUP BY c.name

祝你好运。

于 2013-02-06T17:57:07.837 回答
1

试试这个:

SELECT
    C.Name, COUNT(DISTINCT P.Id) NoProvance, COUNT(CC.Id) NoCities
FROM country C
    JOIN province P
        ON C.Id = P.COUNTRY_ID
    JOIN city CC
        ON P.Id = CC.province_id
WHERE C.Name = 'Thailand'
GROUP BY C.Name

SQL 小提琴演示

于 2013-02-06T17:58:10.093 回答
0

在加入省份之前计算每个省份的城市可能更快:

SELECT c.name          AS "Country Name"
      ,count(p.id)     AS "No. Provinces"
      ,sum(ci.city_ct) AS "No. Cities" 
FROM   country       c
LEFT   JOIN province p ON p.country_id = c.id
LEFT   JOIN (
   SELECT province_id, count(*) AS city_ct FROM city GROUP BY 1
   ) ci ON ci.province_id = p.id
GROUP  BY 1

-> 用于 PostgreSQL 的 sqlfiddle (!)

于 2013-02-06T18:43:02.557 回答