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我已经查看了网络/其他问题以寻求帮助,但无法完全弄清楚并假设我没有使用正确的关键字。

我正在尝试根据用户从网络表单的下拉菜单中选择的值来做某事。逻辑是;

  • 用户从下拉列表中选择一个选项
  • 该脚本检查该选项是否在数组 1,2,3,4 中
  • 根据它所在的数组,它显示不同的 HTML div

这在我的脑海中听起来很简单,但我不知道从哪里开始。一如既往地感谢任何帮助。

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1 回答 1

0

这样做真的很快,所以我相信它可以改进。

我想到了两种方法,第一种是使用.indexOf

<script type="text/javascript>
    $(document).ready(function()
    {
        var selectedVal = 'asd';
        var selectedIndex;

        var arrayHolder; //should hold the array the value was found in
        var arr1 = ['huh', 'asd'];
        var arr2 = ['asdasd'];
        var arr3 = ['asdasdasd'];
        var arr4 = ['asdasdasdasd'];

        //arr1
        arrayHolder = arr1;
        selectedIndex = arrayHolder.indexOf('asd');

        if (!selectedIndex)
        {
            //arr2
            arrayHolder = arr2;
            selectedIndex = arrayHolder.indexOf('asd');

            if (!selectedIndex)
            {
                //arr3
                arrayHolder = arr3;
                selectedIndex = arrayHolder.indexOf('asd');

                if (!selectedIndex)
                {
                    //arr4
                    arrayHolder = arr4;
                    selectedIndex = arrayHolder.indexOf('asd');

                    if (!selectedIndex)
                    {
                        alert(selectedVal + ' not found in all 4 arrays.');
                    }
                }
            }
        }

        //By here, you should know if a value was found and in which array
        alert(arrayHolder);//contains the array in which the value was found
        alert(selectedIndex);//The index number where it was found

        //test
        console.log(arrayHolder[selectedIndex]);
    });
</script>

第二种方法是使用 jQuery 的inArray

<script type="text/javascript>
    $(document).ready(function()
    {
        var selectedVal = 'asd';
        var selectedIndex;

        var arrayHolder; //should hold the array the value was found in
        var arr1 = ['huh', 'asd'];
        var arr2 = ['asdasd'];
        var arr3 = ['asdasdasd'];
        var arr4 = ['asdasdasdasd'];

        //check first array
        arrayHolder = arr1;
        selectedIndex = $.inArray(selectedVal, arrayHolder);

        //check if found in first array, if not check next array
        if (!selectedIndex)
        {
            arrayHolder = arr2;
            selectedIndex = $.inArray(selectedVal, arrayHolder);

            //check if found in second array, if not check next array
            if (!selectedIndex)
            {
                arrayHolder = arr3;
                selectedIndex = $.inArray(selectedVal, arrayHolder);

                //check if found in third array, if not check next array
                if (!selectedIndex)
                {
                    arrayHolder = arr4;
                    selectedIndex = $.inArray(selectedVal, arrayHolder);

                    //check if found in third array, if not check next array
                    if (!selectedIndex)
                    {
                        alert(selectedVal + ' not found in all 4 arrays.');
                    }
                }
            }
        }

        //By here, you should know if a value was found and in which array
        alert(arrayHolder);//contains the array in which the value was found
        alert(selectedIndex);//The index number where it was found

        //test
        console.log(arrayHolder[selectedIndex]);
    });
</script>

.indexOf 支持

注意: 并非所有浏览器都支持 .indexOf()(特别是 IE)。所以如果你想使用 indexOf(),你应该首先使用下面的代码,在所有浏览器中添加对它的支持(代码归功于 mozilla)。

<script type="text/javascript">
        if (!Array.prototype.indexOf)
        {
          Array.prototype.indexOf = function(elt /*, from*/)
          {
            var len = this.length >>> 0;

            var from = Number(arguments[1]) || 0;
            from = (from < 0)
                 ? Math.ceil(from)
                 : Math.floor(from);
            if (from < 0)
              from += len;

            for (; from < len; from++)
            {
              if (from in this &&
                  this[from] === elt)
                return from;
            }
            return -1;
          };
        }
</script>
于 2013-02-13T04:09:06.517 回答