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Lets say I have this array:

var likes = [4,7,3,11,3,73,78,34,7,13];

However, I'm only capable of use the length of 5 due to some restrictions. So I want to "convert" it to an array lenght of 5, and sum the other positions, by distribute them equally.

Does anybody have a clue how can I do this?

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3 回答 3

1

由于不太清楚您到底想要什么，我也会发布一个答案。无论您的输入有多大，此代码都将在您的输出数组中保持 5 的固定长度。

var input = [4,7,3,11,3,73,78,34,25,7,13,19,2],
    max = 5,
    out = [];

var adjacentItems = Math.ceil(input.length / max);
for(var i=0; i<input.length; i += adjacentItems) {
    var aSum = 0;
    for(var j=i; j<Math.min(i+adjacentItems, input.length); j++) {
        aSum += input[j];
    }
    out.push(aSum);
}

看看小提琴

于 2013-02-06T13:30:17.623 回答
1

也许这会解决你的问题：

var likes = [4,7,3,11,3,73,78,34,7,13],
    result_array = [ ];

for(var i = 0; i < likes.length; i++)
{
   if(i % 2)
   {
       var new_val = likes[i - 1] + likes[i];
       result_array.push(new_val);
   }
}

在这里查看一个工作的jsFiddle。

这将导致新数组包含[ 11, 14, 76, 112, 20 ]，并且在将新值添加到初始数组时同样会增加长度。

于 2013-02-06T13:05:20.193 回答
0

最后，我想我找到了答案！:) 如果您有任何建议，请发表评论！

var likes = [1,2,3,4,5,6,7,8,9,10];
    result_array = [];
    result_array2 = [];    
    max = 8;

if (likes.length>max){
    result_array = likes;
    for (var i = 0; i < max; i++) {
            var res = (likes.length - max) / max
            var new_val = (result_array[i] + (result_array[i+1] * res));
            result_array2.push(new_val);

    }

result_array = [];
result_array = result_array2;

}else{
result_array=likes
}

alert(result_array);

请在此处检查代码

于 2013-02-07T16:13:11.627 回答