我想知道,如何以编程方式读取特定号码的短信?我知道如何使用内容提供者阅读短信,但不确定我是否应该使用“人”栏或“地址”栏或完全不同的方式请帮助谢谢
问问题
9397 次
3 回答
7
它将列出来自指定号码的消息。
Uri mSmsinboxQueryUri = Uri.parse("content://sms/inbox");
Cursor cursor1 = getContentResolver().query(mSmsinboxQueryUri,new String[] { "_id", "thread_id", "address", "person", "date","body", "type" }, null, null, null);
startManagingCursor(cursor1);
String[] columns = new String[] { "address", "person", "date", "body","type" };
if (cursor1.getCount() > 0) {
String count = Integer.toString(cursor1.getCount());
while (cursor1.moveToNext()){
String address = cursor1.getString(cursor1.getColumnIndex(columns[0]));
if(address.equalsIgnoreCase("number")){ //put your number here
String name = cursor1.getString(cursor1.getColumnIndex(columns[1]));
String date = cursor1.getString(cursor1.getColumnIndex(columns[2]));
String body = cursor1.getString(cursor1.getColumnIndex(columns[3]));
String type = cursor1.getString(cursor1.getColumnIndex(columns[4]));
Log.d("*******", "body="+body);
}
}
}
但是我遇到了"content://mms-sms/conversations/"
我认为它会在帮助下直接返回特定号码的整个对话thread_id
,检查一下
于 2013-02-06T05:07:10.950 回答
2
您可以使用 SelectionArgs 来提高效率:
String[] phoneNumber = new String[] { "+18839494492" }; //the wanted phone number
Cursor cursor1 = getContentResolver().query(Uri.parse("content://sms/inbox"), new String[] { "_id", "thread_id", "address", "person", "date","body", "type" }, "address=?", phoneNumber, null);
通过此更改,您只能从想要的号码中获取短信,而无需浏览所有收到的短信。
于 2014-05-09T16:51:39.000 回答
0
public class SmsReceiver extends BroadcastReceiver {
String specificPhoneNumber = "No you want";
public void onReceive(Context context, Intent intent)
{
//---get the SMS message passed in---
Bundle bundle = intent.getExtras();
SmsMessage[] msgs = null;
String str = "";
if (bundle != null)
{
//---retrieve the SMS message received---
Object[] pdus = (Object[]) bundle.get("pdus");
msgs = new SmsMessage[pdus.length];
for (int i=0; i<msgs.length; i++){
msgs[i] = SmsMessage.createFromPdu((byte[])pdus[i]);
String phNum = msgs[i].getOriginatingAddress();
str += msgs[i].getMessageBody().toString();
if (specificPhoneNumber.equals(phNum))
{
Uri uri = Uri.parse("content://sms/inbox");
ContentResolver contentResolver = context.getContentResolver();
String where = "address="+phNum;
Cursor cursor = contentResolver.query(uri, new String[] { "_id", "thread_id"}, where, null,
null);
while (cursor.moveToNext()) {
long thread_id = cursor.getLong(1);
where = "thread_id="+thread_id;
Uri thread = Uri.parse("content://sms/inbox");
context.getContentResolver().delete(thread, where, null);
}
Intent l = new Intent(context,AgAppMenu.class);
l.putExtra("msg",str);
l.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(l);
}
}
}
}
}
于 2013-02-06T05:00:21.620 回答