sql - 如何在sql中获取最少的行

Question

嗨，我想从 Sql Server 表中检索具有最小值但不应更改行中数据顺序的行，即不应将 Id 旁边的数据排序错误我正在尝试获取结果，但我不是对我得到的结果感到满意。我知道我可以使用 where 子句来阻止数据放错顺序，但是因为我想将它与 java 向量相关联，所以我不能使用该选项。这是我目前正在编码的内容 rm_id 是我的 ID，但我到处都是最小值，即 0

SELECT   b.rm_id AS 'REMITTANCE ID',
     min(b.[1]) AS 'Re. 1',
     min(b.[2]) AS 'Rs. 2',
     min(b.[5]) AS 'Rs. 5',
     min(b.[10]) AS 'Rs. 10',
     min(b.[20]) AS 'Rs. 20',
     min(b.[50]) AS 'Rs. 50',
     min(b.[100]) AS 'Rs. 100',
     min(b.[500]) AS 'Rs. 500',
     min(b.[1000]) AS 'Rs. 1000',
     min(b.[tp]) AS 'T.P',
     min(b.[tv]) AS 'T.V'
FROM     trans_det AS b
GROUP BY b.rm_id WITH ROLLUP
ORDER BY rm_id DESC;

Answer 1

我怀疑你可能想要这个：

select top 1 td.* from trans_det order by b.[1] union all
select top 1 td.* from trans_det order by b.[2] union all
select top 1 td.* from trans_det order by b.[5] union all
. . .
select top 1 td.* from trans_det order by b.tv

这将返回每个值具有最小值的行集。