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我有这张USERS表，用户可以是两种不同类型（A 和 B）。我需要显示每周每种类型的汇总报告。到目前为止，我的查询运行良好，除了一些星期没有正确分组。在下面的示例中，从 1 月 28 日开始的那一周应该有一行，而不是两行。

Week Starts |Week| Type A | Type B
------------+----+--------+------
2013-02-04  | 14 |  2     | 26
2013-01-28  | 13 |  5     | 191
2013-01-28  | 13 |  0     | 24
2013-01-21  | 12 |  1     | 134
2013-01-21  | 12 |  0     | 20
2013-01-14  | 11 |  1     | 143
2013-01-14  | 11 |  0     | 2
2013-01-07  | 10 |  0     | 233
2013-01-07  | 10 |  0     | 23
2012-12-31  | 9  |  0     | 12
2012-12-31  | 9  |  4     | 164
2012-12-31  | 9  |  0     | 20

SQL

;with cte as
(
select DATEADD(m,-3,GETDATE()) firstday, DATEADD(m,-3,GETDATE()) + 6 - DATEDIFF(day, 0, DATEADD(m,-3,GETDATE())) %7 lastday,  1 week
union all
select lastday + 1, case when GETDATE() < lastday + 7 then GETDATE() else lastday + 7 end,  week + 1
from cte
where lastday < GETDATE()
)
SELECT
    cast(firstday as date) 'Week Starts',
    cte.week as 'Week',
    Sum(CASE WHEN USR_TYPE = 'A' THEN 1 ELSE 0 END) As 'Type A',
    Sum(CASE WHEN USR_TYPE = 'B' THEN 1 ELSE 0 END) As 'Type B'
FROM cte left join USERS
ON cte.firstday <= USERS.CREATED
AND cte.lastday > USERS.CREATED
GROUP BY cte.week, cte.firstday, cte.lastday, DATEPART(YEAR,USERS.CREATED), DATEPART(wk,USERS.CREATED)
ORDER BY week desc

我究竟做错了什么？

4

1 回答 1

5

在没有从您的表格中看到任何数据的情况下，users我将进行猜测。

您在 CTE 中生成的日期列表包括time.

您可能需要将cast()您的firstday和lastday值作为 adate或立即生成列表。

查看SQL Fiddle 演示

来自您的 CTE 和新日期的样本：

| CASTFIRSTDAY | CASTLASTDAY | WEEK |                        FIRSTDAY |                         LASTDAY |
---------------------------------------------------------------------------------------------------------
|   2012-11-05 |  2012-11-11 |    1 | November, 05 2012 20:08:10+0000 | November, 11 2012 20:08:10+0000 |
|   2012-11-12 |  2012-11-18 |    2 | November, 12 2012 20:08:10+0000 | November, 18 2012 20:08:10+0000 |
|   2012-11-19 |  2012-11-25 |    3 | November, 19 2012 20:08:10+0000 | November, 25 2012 20:08:10+0000 |
|   2012-11-26 |  2012-12-02 |    4 | November, 26 2012 20:08:10+0000 | December, 02 2012 20:08:10+0000 |
|   2012-12-03 |  2012-12-09 |    5 | December, 03 2012 20:08:10+0000 | December, 09 2012 20:08:10+0000 |
|   2012-12-10 |  2012-12-16 |    6 | December, 10 2012 20:08:10+0000 | December, 16 2012 20:08:10+0000 |

您可能想要编辑您的 CTE 以返回date唯一的值：

;with cte as
(
    select 
        cast(DATEADD(m,-3,GETDATE()) as date) firstday, 
        cast(DATEADD(m,-3,GETDATE()) + 6 - DATEDIFF(day, 0, DATEADD(m,-3,GETDATE())) %7 as DATE) lastday,  
        1 week
    union all
    select 
        cast(DATEADD(DAY, 1, lastday) as date), 
        case 
            when cast(GETDATE() as date) < cast(DATEADD(DAY, 7, lastday) as date)
            then cast(GETDATE() as date) 
            else cast(DATEADD(DAY, 7, lastday) as date)
        end,  
        week + 1
    from cte
    where cast(lastday as date)  < cast(GETDATE() as date) 
)
select *
from cte

请参阅带有演示的 SQL Fiddle

于 2013-02-05T20:07:15.913 回答