f# - F# 等效于 toLookup

Question

鉴于这种：

[
    ("A","A122");
    ("A","A123");
    ("B","B122");
    ("B","B123");
    ("C","C122");
]

有没有标准功能来获得这个？

[
    ("A",["A122";"A123"]);
    ("B",["B122";"B123"]);
    ("C",["C122"])
]

我想到了 Seq.distinctBy、List.partition、Set、Map，但它们似乎都不是我想要的。

谢谢...在我等待的时候，我会尝试自己动手:)

Answer 1

愚蠢的我，我没有注意到 Seq.groupBy！

[
    ("A","A122");
    ("A","A123");
    ("B","B122");
    ("B","B123");
    ("C","C122");
]
 |> Seq.groupBy (fun (a, b) -> a)
 |> Seq.map (fun (a, b) -> (a, Seq.map snd b))

输出 ：

seq
[("A", seq ["A122"; "A123"]); ("B", seq ["B122"; "B123"]);
 ("C", seq ["C122"])]

Answer 2

对于 O(1) 查找：

[
    ("A","A122");
    ("A","A123");
    ("B","B122");
    ("B","B123");
    ("C","C122");
]
|> Seq.groupBy fst
|> dict