27

我有一个包含 XML 列的表：

CREATE TABLE Batches( 
   BatchID int,
   RawXml xml 
)

xml 包含以下项目：

<GrobReportXmlFileXmlFile>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>

我想要的是生成一个集合，其中包含：

OrganizationReportReferenceNumber  OrganizationNumber
=================================  ==================
1                                  4
2                                  4
3                                  4
4                                  4

我试过了：

SELECT 
    foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
    foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM CDRBatches.RawXML.query('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') foo

但这不起作用。我试过了：

SELECT 
    foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
    foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM RawXML.nodes('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') bar(foo)

但这不起作用。XPath表达式_

/GrobReportXmlFileXmlFile/GrobReport/ReportHeader

是正确的; 在任何其他 xml 系统中它返回：

<ReportHeader>
    <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>

因此，从我想看到的查询中可以明显看出。在阅读了十几个 Stackover 问题和答案之后，我离解决问题还差得远。

4

4 回答 4

40 
SELECT  b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    Batches b
CROSS APPLY b.RawXml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol);

演示：SQLFiddle

于 2013-02-05T17:31:59.300 回答
7

这行得通，已经过测试...

SELECT  n.c.value('OrganizationReportReferenceIdentifier[1]','varchar(128)') AS 'OrganizationReportReferenceNumber',  
        n.c.value('(OrganizationNumber)[1]','varchar(128)') AS 'OrganizationNumber'
FROM    Batches t
Cross   Apply RawXML.nodes('/GrobXmlFile/Grob/ReportHeader') n(c)
于 2013-02-05T17:20:11.383 回答
2

尝试这个：

SELECT RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationReportReferenceIdentifier/node())[1]','varchar(50)') AS ReportIdentifierNumber,
       RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationNumber/node())[1]','int') AS OrginazationNumber
FROM Batches
于 2013-02-05T17:09:00.053 回答
0

如果表中只有一个 xml，则可以分两步进行转换：

CREATE TABLE Batches( 
   BatchID int,
   RawXml xml 
)

declare @xml xml=(select top 1 RawXml from @Batches)

SELECT  --b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    @xml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol)
于 2018-11-26T09:24:07.887 回答