php - 以秒和分钟范围显示时间值背后的逻辑

Question

我想知道显示时间戳（如 x 分钟前或 x 小时前）以及几个小时后显示确切时间（如下午 7:57 发布的确切时间）背后使用的逻辑，就像他们在邮件网站和 Twitter 等中所做的那样。

我怎么知道何时显示秒/分钟/小时范围以及何时以上午/下午格式显示实际时间？请建议用于实现此目的的业务逻辑。

Answer 1

从 php 手册：

<?php
function nicetime($date)
{
    if(empty($date)) {
        return "No date provided";
    }

    $periods         = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
    $lengths         = array("60","60","24","7","4.35","12","10");

    $now             = time();
    $unix_date         = strtotime($date);

       // check validity of date
    if(empty($unix_date)) {    
        return "Bad date";
    }

    // is it future date or past date
    if($now > $unix_date) {    
        $difference     = $now - $unix_date;
        $tense         = "ago";

    } else {
        $difference     = $unix_date - $now;
        $tense         = "from now";
    }

    for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
        $difference /= $lengths[$j];
    }

    $difference = round($difference);

    if($difference != 1) {
        $periods[$j].= "s";
    }

    return "$difference $periods[$j] {$tense}";
}

$date = "2009-03-04 17:45";
$result = nicetime($date); // 2 days ago

?>

http://www.php.net/manual/de/function.time.php#89415

Answer 2

使用 PHP 以常规方式打印时间戳，并使用 jQuery 的 timeago 插件来做一些花哨的事情。

Answer 3

你可以使用这样的东西

$time = $now - $time;

if ($time < 60) {
    $name = "second";
}
elseif ($time < 3600)
{
    $time /= 60;
    $name = "minute";
}
elseif ($time < 86400)
{
    $time /= 3600; //86400;
    $name = "hour";
}
elseif ($time < 604800)
{
    $time /= 86400; //604800;
    $name = "day";
}
elseif ($time < 31536000)
{
    $time /= 604800; //31536000;
    $name = "week";
}
else
{
    $time /= 31536000;
    $name = "year";
}