php - PHP/MySQL 使用带 LIMIT 的 ORDER BY

Question

我大致按照这个链接创建了一个分页：

http://www.awcore.com/dev/1/3/Create-Awesome-PHPMYSQL-Pagination_en#toggle

很酷。虽然我的查询有问题。

它像这样工作正常：

require 'includes/function.php';

    $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
    $limit = 8;
    $startpoint = ($page * $limit) - $limit;

    $statement = "cars WHERE deleted = 'no'";

$query = mysql_query("SELECT * FROM {$statement} LIMIT {$startpoint}, {$limit} ");

while ($row = mysql_fetch_assoc($query)) {

但是，当我尝试向其中添加 ORDER BY 时，如下所示：

需要'includes/function.php'；

    $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
    $limit = 8;
    $startpoint = ($page * $limit) - $limit;

    $statement = "cars WHERE deleted = 'no'";

$query = mysql_query("SELECT * FROM {$statement} LIMIT {$startpoint}, {$limit} ORDER BY model DESC");

while ($row = mysql_fetch_assoc($query)) {

或者只是像这样更改语句：

$statement = "rcr_cars WHERE deleted = 'no' ORDER BY model DESC";

我收到此错误：

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in filepath/myfile.php on line 79.

第 79 行是这一行：

 while ($row = mysql_fetch_assoc($query)) {

谁能告诉我我如何没有正确使用 ORDER BY，这让我很困惑。：/

Answer 1

尝试如下查询

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit} ");

你出错的地方是 LIMIT 应该在 ORDER BY 之后。阅读更多

Answer 2

更改查询：

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit}") ;

Answer 3

$query = mysql_query("SELECT * FROM {$statement} ORDER BY model DESC LIMIT {$startpoint}, {$limit} ");