1

实际上我们有 2 个模型

class Event(Basetable):
    title = models.CharField(max_length=150)
    event_description = models.TextField()
    image = ThumbnailerImageField(upload_to=get_eventlogo_path, resize_source=dict(size=(700, 0), crop='smart'),)
    category = models.ManyToManyField("EventCategory")
    venue = models.ForeignKey(Venue,null=True)

class Venue(models.Model):
venue   = models.CharField(max_length=100)
address1 = models.CharField(max_length=200)
address2 = models.CharField(max_length=200,blank=True)
slug = models.CharField(max_length=150,blank=True,null=True)
country = models.ForeignKey(Countries,null=True,blank=True,on_delete=models.SET_NULL)
state = models.ForeignKey(States,null=True,on_delete=models.SET_NULL)
city = models.ForeignKey(City,null=True,on_delete=models.SET_NULL)

美味的代码

class EventResource(ModelResource):
venue      = fields.ForeignKey(VenueResource, 'venue')    

class Meta:
    queryset = Event.objects.filter(status='P').order_by('-id').distinct()
    resource_name = 'eventlist'
    filtering = {
        "slug": ('exact', 'startswith',),
        "title": ALL,
    }

我的问题是我需要使用场地中的城市来获取活动结果

ex www.example.com/api/v1/eventlist/?format=json&city="chicago" 但它不会来帮助我

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1 回答 1

3

您必须允许按场地过滤：

filtering = { 'venue': ALL_WITH_RELATIONS

               }

该链接将起作用。www.example.com/api/v1/eventlist/?format=json&venue_city_name="chicago " _

于 2013-02-05T09:39:42.840 回答