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当我们在表中插入或更新数据时，有时我希望将主键和表名插入到另一个表中。
我需要这个在一天结束时进行核对，今天更新的所有表格。

请建议。谢谢你。

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3 回答 3

3

看看 CDC -变更数据捕获

或者 Paul Nielsen 的AutoAudit。

于 2013-02-05T07:07:37.923 回答
0

我已经解决了这样的问题......我希望它能回答你的问题。

  1. 创建几个测试表进行演示
  2. 创建 SQL 以在所有表​​上创建触发器
  3. 简单的插入语句。 
   CREATE TABLE [dbo].[log_table](
          [table_name] [varchar](1000) NULL,
          [column_name] [varchar](1000) NULL,
          [column_value] [varchar](1000) NULL,
          [datetime] [datetime] NULL
        ) 
        GO

    CREATE TABLE [dbo].[Animals](
        [AnimalID] [int] IDENTITY(1,1) NOT NULL,
        [AnimalName] [varchar](50) NULL,
     CONSTRAINT [PK_Animals] PRIMARY KEY CLUSTERED 
    ([AnimalID] ASC)
    )

    GO

    CREATE TABLE [dbo].[Countries](
        [CountryID] [uniqueidentifier] NOT NULL,
        [CountryName] [varchar](50) NULL,
     CONSTRAINT [PK_Countries] PRIMARY KEY CLUSTERED 
    ([CountryID] ASC))
    ALTER TABLE [dbo].[Countries] ADD  CONSTRAINT [DF_Countries_countryID]  DEFAULT (newid()) FOR [CountryID]
    GO 

    SELECT 
  ' IF OBJECT_ID ('+ CHAR(39) + SCHEMA_NAME(tbl.SCHEMA_ID) + '.trg_' + tbl.name + CHAR(39) + ',''TR'') IS NOT NULL ' + 
  ' DROP TRIGGER ' + SCHEMA_NAME(tbl.SCHEMA_ID) + '.trg_'+ tbl.name + ';' + 
  ' EXEC (' + CHAR(39) +
  ' CREATE TRIGGER ' + SCHEMA_NAME(tbl.SCHEMA_ID) + '.trg_'+ tbl.name + 
  ' ON '+ SCHEMA_NAME(tbl.SCHEMA_ID) + '.' + tbl.name + ' FOR INSERT,UPDATE AS ' + 
  ' DECLARE @newval varchar(1000) ' + 
  ' SELECT @newval ='+ COL_NAME(tbl.object_id, ic.column_id) + ' FROM INSERTED' + 
  ' INSERT INTO log_table(table_name,column_name,column_value,datetime) VALUES('+ 
  CHAR(39)+ CHAR(39) + SCHEMA_NAME(tbl.SCHEMA_ID)  +'.'+  tbl.name + CHAR(39)+ CHAR(39) + ' ,'+ 
  CHAR(39)+ CHAR(39) + COL_NAME(tbl.object_id, ic.column_id) + CHAR(39)+ CHAR(39) + ' ,'+     
  '@newval,getdate()'+ ')' + CHAR(39)+ ')'
FROM
  sys.tables AS tbl
  INNER JOIN  sys.key_constraints AS kc ON kc.parent_object_id = tbl.object_id
  INNER JOIN sys.indexes AS i  ON kc.unique_index_id = i.index_id  AND kc.parent_object_id = i.object_id
  INNER JOIN sys.index_columns AS ic  ON i.object_id = ic.object_id  AND i.index_id = ic.index_id
WHERE  tbl.type = 'U'  AND ic.is_included_column = 0 and tbl.name NOT IN ('sysdiagrams','log_table')
ORDER BY  tbl.object_id,  ic.key_ordinal;

现在插入我们的表格

INSERT INTO Countries(CountryName) VALUES('South Africa')
INSERT INTO Countries(CountryName) VALUES('USA')
INSERT INTO Countries(CountryName) VALUES('Brazil')
INSERT INTO Countries(CountryName) VALUES('Zimbabwe')
INSERT INTO Countries(CountryName) VALUES('Africa is not a country')


INSERT INTO Animals(AnimalName) VALUES ('Lion')
INSERT INTO Animals(AnimalName) VALUES ('African Elephant')
INSERT INTO Animals(AnimalName) VALUES ('Rhinoceros')
INSERT INTO Animals(AnimalName) VALUES ('Leopard')
INSERT INTO Animals(AnimalName) VALUES ('Cape Buffalo')
于 2013-02-05T09:51:36.113 回答
0 
SELECT name
FROM sys.objects
WHERE DATEDIFF(D,modify_date, GETDATE()) < 1

通过使用此查询，您可以获得数据库的所有修改。代替 1，您可以指定不希望看到更改的天数。

于 2013-02-05T07:09:07.190 回答