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此 SQL 查询完全执行执行时所需的操作。我正在寻找等效的 JPA 标准？基本上从一对多关系中获取设备实体和最新（最大）GPS坐标

SELECT DISTINCT t0.DEVICE_I, t0.ACTIVE_S, t0.APP_CONFIG_I, t0.PREV_APP_CONFIG_I, 
t0.APP_CONFIG_CONFIRMED_S, t0.APP_CONFIG_RECEIPT_D, t0.APP_CONFIG_SENT_S, t0.CHANNEL_X, 
t0.CREATION_TS, t0.CREATION_USER_I, t0.DEST_QUEUE_C, t0.DIVISION_C, t0.LAN_IP_X, 
t0.LAST_UPDATE_TS, t0.LAST_UPDATE_USER_I, t0.MOBILE_IP_X, t0.ORIGIN_MP_I, 
t0.PREV_CHANNEL_X, t0.TELEPHONE_NUMBER_X, t0.VERSION_X, t1.DEVICE_I, t1.COORDINATE_I, 
t1.CREATION_TS, t1.CREATION_USER_I, t1.GENERATED_TS, t1.GPGGA_X, t1.GPGSA_X, 
t1.GPGSV_X, t1.GPRMC_X, t1.GPVTG_X, t1.LAST_UPDATE_TS, t1.LAST_UPDATE_USER_I, 
t1.WORK_ORDER_NUMBER_I 

FROM DEVICE t0, GPS_COORD t1 

WHERE  t0.DEVICE_I = t1.DEVICE_I AND  
t1.GENERATED_TS IN ( select max(GENERATED_TS)
       from GPS_COORD
      group by DEVICE_I )
ORDER BY t1.DEVICE_I ASC, t1.GENERATED_TS DESC

下面的 java 代码几乎就在那里，并生成以下查询，其中缺少 GpsCoord 所需的连接字段。如果完成获取，则包含这些字段，但稍后在子查询的 where 子句中需要加入：

    CriteriaBuilder criteriaBuilder = em.getCriteriaBuilder();

    CriteriaQuery<Device> cq = criteriaBuilder.createQuery(Device.class);

    Root<Device> device = cq.from(Device.class);
    cq.distinct(true);

    Join<Device, GpsCoord> j = device.join(Device_.gpsCoords, JoinType.LEFT);
    //Fetch<Device,GpsCoord> f = device.fetch(Device_.gpsCoords);
    
    CriteriaQuery<Device> select = cq.select(device);


    Subquery<Timestamp> sq = cq.subquery(Timestamp.class);
    Root<GpsCoord> gpsCoord = sq.from(GpsCoord.class);

    sq.select(criteriaBuilder.greatest(gpsCoord.get(GpsCoord_.generatedTs)));
    sq.groupBy(gpsCoord.get(GpsCoord_.device).get(Device_.deviceI));
    select.where(j.get(GpsCoord_.generatedTs).in(sq));
    
    
    TypedQuery<Device> query = this.getEntityManager().createQuery(cq);

生成的查询缺少加入操作中的 GpsCoord 文件

SELECT DISTINCT t0.DEVICE_I, t0.ACTIVE_S, t0.APP_CONFIG_I, t0.PREV_APP_CONFIG_I,     
t0.APP_CONFIG_CONFIRMED_S, t0.APP_CONFIG_RECEIPT_D, t0.APP_CONFIG_SENT_S, 
t0.CHANNEL_X,     t0.CREATION_TS, t0.CREATION_USER_I, t0.DEST_QUEUE_C, t0.DIVISION_C, 
t0.LAN_IP_X, t0.LAST_UPDATE_TS, t0.LAST_UPDATE_USER_I, t0.MOBILE_IP_X, t0.ORIGIN_MP_I, 
t0.PREV_CHANNEL_X, t0.TELEPHONE_NUMBER_X, t0.VERSION_X 

FROM SPW_OWN.DEVICE t0, SPW_OWN.GPS_COORD t1 

WHERE (t1.GENERATED_TS IN (SELECT MAX(t2.GENERATED_TS) FROM SPW_OWN.GPS_COORD t2, 
SPW_OWN.DEVICE t3 WHERE t2.DEVICE_I = t3.DEVICE_I GROUP BY t3.DEVICE_I)) 

AND t0.DEVICE_I = t1.DEVICE_I(+)

像这样使用 CriteriaQuery 中的多选会在执行时生成正确的 SQL，但是会出现以下异常

Caused by: java.lang.Exception: java.lang.RuntimeException: Can not find constructor for "class Device" with argument types "[class java.lang.String ... java.sql.Timestamp]" to fill data.

通话后被抛出：

CriteriaQuery<Device> select = cq.multiselect(
                    //"deviceI",
                    device.get(Device_.deviceI),
                    //"activeS",
                    device.get(Device_.activeS),
                    //"appConfigConfirmedS",
                    device.get(Device_.appConfigConfirmedS),
                    //"appConfigReceiptD",
                    device.get(Device_.appConfigReceiptD),
                    //"appConfigSentS",
                    device.get(Device_.appConfigSentS),
                    //"channelX",
                    device.get(Device_.channelX),
                    //"destQueueC",
                    device.get(Device_.destQueueC),
                    //"lanIpX",
                    device.get(Device_.lanIpX),
                    //"mobileIpX",
                    device.get(Device_.mobileIpX),
                    //"prevChannelX",
                    device.get(Device_.prevChannelX),
                    //"telephoneNumberX",
                    device.get(Device_.telephoneNumberX),
                    //"versionX"
                    device.get(Device_.versionX),
                    //"device",
                    j.get(GpsCoord_.device),
                    //"gpggaX",
                    j.get(GpsCoord_.gpggaX),
                    //"gprmcX",
                    j.get(GpsCoord_.gprmcX),
                    //"gpgsaX",
                    j.get(GpsCoord_.gpgsaX),
                    //"gpgsvX",
                    j.get(GpsCoord_.gpgsvX),
                    //"gpvtgX"
                    j.get(GpsCoord_.gpvtgX),
                    j.get(GpsCoord_.generatedTs)
                    );
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1 回答 1

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几个问题，

  • 你打电话给 sq.from(GpsCoord.class); 两次
  • 使用 device.fetch(Device_.gpsCoords); 还将获取对象，并将加入它两次
  • 你的输入不正确，应该是，

select.where(criteriaBuilder.get(path).in(sq));

于 2013-02-05T15:23:20.190 回答