我正在尝试为数据库中的每个问题插入每个答案。问题是问题可能没有答案,所以我尝试了下面的代码,但如果问题没有答案,它不会插入数据库行,我想做的是,如果没有答案,则显示该问题列No Answer
下的字符串Answer
:
$answersql = "INSERT INTO Answer (QuestionId, Answer)
VALUES (?, ?)";
if (!$insertanswer = $mysqli->prepare($answersql)) {
// Handle errors with prepare operation here
echo __LINE__.': '.$mysqli->error;
}
if( $insert && $insertanswer)
{
$c = count($_POST['numQuestion']);
$question_ids = array();
for($i = 0; $i < $c; $i++ )
{
... //Question INSERT goes here
$questionId = $mysqli->insert_id;
$question_ids[$questionNo] = $questionId;
}
$results = $_POST['value'];
foreach($results as $id => $value)
{
$answer = $value;
$quesid = (int)$question_ids[$id];
foreach($value as $answer)
{
if($answer == '' || $answer === null){
$answer = 'No Answer';
}
$insertanswer->bind_param("is", $quesid, $answer);
$insertanswer->execute();
if ($insertanswer->errno) {
// Handle query error here
echo __LINE__.': '.$insertanswer->error;
break 7;
}
}
}
//close your statements at the end
$insertanswer->close();
}
来自['value']
输入:
var $newBtn = $(("<input class='answerBtnsRow answers' type='button' style='display:%s;' onclick='btnclick(this, " + gQuestionIndex + ");' />").replace('%s', $this.is(':visible') ? 'inline-block' : 'none')).attr('name', "value[" + gQuestionIndex + "][]").attr('value', $this.val()).attr('class', $this.attr('class')).attr('id', $this.attr('id') + 'Row');
更新:
下面是表的 SHOW CREATE TABLE Answer
:
CREATE TABLE `Answer` (
`AnswerId` int(10) NOT NULL AUTO_INCREMENT,
`QuestionId` int(10) NOT NULL,
`Answer` varchar(10) DEFAULT NULL,
PRIMARY KEY (`AnswerId`)
) ENGINE=InnoDB AUTO_INCREMENT=280 DEFAULT CHARSET=utf8
下面是一个 var 转储,如果我将问题 1 设置为有答案B
并将C
问题 2 设置为根本没有答案,它会输出以下内容:
var_dump($question_ids);
var_dump($results);
array(2) {
[1]=> int(247)
[2]=> int(248)
}
array(1) {
[1]=> array(2) {
[0]=> string(1) "B"
[1]=> string(1) "C" }
}