1

我最近编写了一个代码来更新我在博客上的帖子。它在本地主机上完美运行。但是当我把它上传到网上时，它不再起作用了。奇怪的是它甚至没有显示错误，所以我不知道在哪里看。有人可以帮帮我吗 ？

require('config.php');
$query = "SELECT * FROM project ORDER BY idproject DESC";
$result = mysqli_query($verbinding, $query ) or die (mysqli_error('kan geen verbinding maken met de database'));
if(isset($_POST['editBut'])){
    $editTitle = $_POST['editName'];
    $editThis = mysqli_query($verbinding, "SELECT * FROM project WHERE title = '".$editTitle."'");
    $values = mysqli_fetch_assoc($editThis);
}
if(isset($_POST['update'])){
    $editedTitle = $_POST['newTitle'];
    $editedText = $_POST['newTekst'];
    $oldTitle = $_POST['oldTitle'];
    $date = $_POST['datum'];
    $updater = mysqli_query($verbinding, "UPDATE Project SET title='".$editedTitle."', content='".$editedText."' WHERE title='".$oldTitle."' AND datum='".$date."'");
    echo $updater;
    header('location:editPost.php?id=1');
}
if(isset($_GET['id'])){
    echo 'post has been succesfully updated';
}

<?php if(isset($_POST['editBut'])){ ?>
            <form action="" method="post">
                Title: <input type="text" name="newTitle" value="<?php echo $values['title'] ?>"><br>
                Text: <textarea type="text" name="newTekst" id="newTekst"><?php echo $values['content'] ?></textarea><br>
                <input type="hidden" value="<?php echo $values['title'] ?>" name="oldTitle">
                <input type="hidden" value="<?php echo $values['datum'] ?>" name="datum">
                <input type="submit" name="update" value="Edit post">
            </form>
        <?php } else { ?>
            <p>Find the post you want to edit:</p>
            <form action="" method="post">
                <select name="editName">
                    <?php
                    while ($row = mysqli_fetch_assoc($result)) {
                       ?> <option value="<?php echo $row['title'] ?>"><?php echo $row['title'] ?></option>
                    <?php } ?>
                </select>
                <input type="submit" name="editBut" value="Choose">
            </form>
        <?php } ?>
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1 回答 1

5

在更新查询中，用小写字母替换您的表名。

替换Project为project

于 2013-02-04T12:21:02.590 回答