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我有点想知道该怎么做，但我无法弄清楚。该程序需要能够获取学生姓名和三个考试成绩，然后得到三个分数的平均分（百分比）。之后，您需要将分数（百分比）转换为成绩。

编辑： 我将如何删除成绩中间的空格和“%”？

  • 请按“Enter”开始
  • 输入您的姓名：乔丹·辛普森
  • 初试成绩：67%
  • 第二次考试成绩：78%
  • 第三次考试成绩：89%
  • 最终字母等级：C+
  • 乔丹辛普森测试分数是：78.0 %
  • 是否要重新启动程序？

分级量表：

分级量表

input ('Please press "Enter" to begin')

while True:
    import math

    studentName = str(input('Enter your Name: '))
    firstScore = int(float(input('First test score: ').replace('%', '')))
    secondScore = int(float(input('Second test score: ').replace('%', '')))
    thirdScore = int(float(input('Third test score: ').replace('%', '')))
    scoreAvg = (firstScore + secondScore + thirdScore) / 3

    def grade():
        if scoreAvg >= 93 and <= 100:
            return 'A'
        if scoreAvg <= 92.9 and >= 89:
            return 'A-'
        if scoreAvg <= 88.9 and >= 87:
            return 'B+'
        if scoreAvg <= 86.9 and >= 83:
            return 'B'
        if scoreAvg <= 82.9 and >= 79:
            return 'B-'
        if scoreAvg <= 78.9 and >= 77:
            return 'C+'
        if scoreAvg <= 76.9 and >= 73:
            return 'C'
        if scoreAvg <= 72.9 and >= 69:
            return 'C-'
        if scoreAvg <= 68.9 and >= 67:
            return 'D+'
        if scoreAvg <= 66.9 and >= 60:
            return 'D'
        return 'F'

    print(grade(scoreAvg))
    print(studentName, "test score is: ",scoreAvg,'%')


    endProgram = input ('Do you want to restart the program?')

    if endProgram in ('no', 'No', 'NO', 'false', 'False', 'FALSE'):
        break
4

1 回答 1

5

不太确定您的问题是什么，但这是获得字母等级的更简洁的方法。

>>> scores = [93, 89, 87, 83, 79, 77, 73, 69, 67, 60, 0]
>>> grades = ['A', 'A-', 'B+', 'B', 'B-', 'C+', 'C', 'C-', 'D+', 'D', 'F']
>>> 
>>> def gradeFor(s):
...     grade_scores = zip(scores, grades)
...     for score, grade in grade_scores:
...        if s >= score:
...            return grade

>>> gradeFor(87)
B+
>>> gradeFor(89)
A-
>>> gradeFor(88)
B+
>>> gradeFor(67)
D+
>>> gradeFor(72)
C-
>>> gradeFor(40)
F

另外，你可以做

if endProgram.lower() in ('no', 'false'):
于 2013-02-04T06:01:21.157 回答