c++ - 交互式 Switch 语句

Question

我试图做一个 switch 语句，要求用户输入一封信。取决于输入。用户将获得电子色码图的色码编号。如果颜色不在电子色码表中，则输出“未知颜色”。当用户输入“b”时我遇到了问题。如何让 switch 语句只输出棕色、蓝色或黑色。我不能使用任何 if、else 语句。*/

#include <stdlib.h>         // Directive for Pause
#include <iostream>         // Directive for Input / Output
using namespace std;

int main ()
{
    char first_letter;
    char second_letter;
    char third_letter ;
    char electronic_color_code;

    cout << "Electronic Color Code" << endl << endl;

    cout << "To find out the digit of a particular color code," << endl <<
    "enter a letter: " ;
    cin >> electronic_color_code;
    cout << endl;

    switch (electronic_color_code)
    {
        case 'r':
        case 'R':
            cout << "Red stands for digit 2.";
            break;

        case 'o':
        case 'O':
            cout << "Orange stands for digit 3.";
            break;

        case 'y':
        case 'Y':
            cout << "Yellow stands for digit 4.";
            break;

        case 'v':
        case 'V':
            cout << "Violet stands for digit 7.";
            break;

        case 'w':
        case 'W':
            cout << "White stands for digit 9.";
            break;

        case 'b':
        case 'B':
            cout << "Enter a second letter: ";
            cin >> second_letter;
            cout << endl;
        case 'brows':
        case 'BROWS':
            cout << "Brown stands for digit 1.";
            cout << endl;
            break;

        case 'lue':
        case 'LUE':
            cout << "Enter a third letter: ";
            cin >> third_letter;
            cout << endl;
        case 'a':
        case 'A':
            cout << "Black stands for digit 0.";
            cout << endl;
        case 'u':
        case 'U':
            cout << "Blue stands for digit 6.";
            break;

        case 'g':
        case 'G':
            cout << "Enter the second and third letter" << endl;
            cin >> second_letter >> third_letter ;
        case 'rayd':
        case 'RAYD':
            cout << "Grey stands for the digit 8.";
        case 0:
        case 'reen':
        case 'REEN':
            cout << "Green stands for the digit 5." ;
            break;

        default:
            cout << "Unknown Color";
    }

    cout << endl << endl;
    system ("Pause");        
    return 0;
}

Answer 1

你肯定误解了这个任务。

你怎么能考虑接受一个字符输入并基于它来选择颜色！！！！

如果用户输入是“b”，则无法确定颜色是黑色还是棕色。您需要将整个单词作为用户输入。例如，您需要输入“XXXX”而不是字符串与“黑色”或“棕色”匹配。