我使用这个示例登录 Twitter、发布状态和照片。我用了很长时间。现在 Twitter 需要从 Twitter API 1.0 升级到 Twitter API 1.1。我需要做什么来升级它?我试图用这个库替换旧的库,到目前为止没有问题,但我害怕我没有完全做改变。
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您必须通过 OAUTH ( https://dev.twitter.com/docs/auth/using-oauth ) 登录才能连接。因此,您还必须在 dev.twitter.com 上注册您的应用程序。您可以在此处找到以下示例https://github.com/browep/Android-OAuth-Twitter-Example。
public class Main extends Activity{
public static final String TAG = Main.class.getSimpleName();
public static final String TWITTER_OAUTH_REQUEST_TOKEN_ENDPOINT = "..."; //cannot share more then 2 lins, sorry
public static final String TWITTER_OAUTH_ACCESS_TOKEN_ENDPOINT = "...";
public static final String TWITTER_OAUTH_AUTHORIZE_ENDPOINT = "...";
private CommonsHttpOAuthProvider commonsHttpOAuthProvider;
private CommonsHttpOAuthConsumer commonsHttpOAuthConsumer;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
commonsHttpOAuthProvider = new CommonsHttpOAuthProvider(TWITTER_OAUTH_REQUEST_TOKEN_ENDPOINT,
TWITTER_OAUTH_ACCESS_TOKEN_ENDPOINT, TWITTER_OAUTH_AUTHORIZE_ENDPOINT);
commonsHttpOAuthConsumer = new CommonsHttpOAuthConsumer(getString(R.string.twitter_oauth_consumer_key),
getString(R.string.twitter_oauth_consumer_secret));
commonsHttpOAuthProvider.setOAuth10a(true);
TwDialog dialog = new TwDialog(this, commonsHttpOAuthProvider, commonsHttpOAuthConsumer,
dialogListener, R.drawable.android);
dialog.show();
}
private Twitter.DialogListener dialogListener = new Twitter.DialogListener() {
public void onComplete(Bundle values) {
String secretToken = values.getString("secret_token");
Log.i(TAG,"secret_token=" + secretToken);
String accessToken = values.getString("access_token");
Log.i(TAG,"access_token=" + accessToken);
new Tweeter(accessToken,secretToken).tweet(
"Tweet from sample Android OAuth app. unique code: " + System.currentTimeMillis());
}
public void onTwitterError(TwitterError e) { Log.e(TAG,"onTwitterError called for TwitterDialog",
new Exception(e)); }
public void onError(DialogError e) { Log.e(TAG,"onError called for TwitterDialog", new Exception(e)); }
public void onCancel() { Log.e(TAG,"onCancel"); }
};
public static final Pattern ID_PATTERN = Pattern.compile(".*?\"id_str\":\"(\\d*)\".*");
public static final Pattern SCREEN_NAME_PATTERN = Pattern.compile(".*?\"screen_name\":\"([^\"]*).*");
public class Tweeter {
protected CommonsHttpOAuthConsumer oAuthConsumer;
public Tweeter(String accessToken, String secretToken) {
oAuthConsumer = new CommonsHttpOAuthConsumer(getString(R.string.twitter_oauth_consumer_key),
getString(R.string.twitter_oauth_consumer_secret));
oAuthConsumer.setTokenWithSecret(accessToken, secretToken);
}
public boolean tweet(String message) {
if (message == null && message.length() > 140) {
throw new IllegalArgumentException("message cannot be null and must be less than 140 chars");
}
// create a request that requires authentication
try {
HttpClient httpClient = new DefaultHttpClient();
Uri.Builder builder = new Uri.Builder();
builder.appendPath("statuses").appendPath("update.json")
.appendQueryParameter("status", message);
Uri man = builder.build();
HttpPost post = new HttpPost("http://twitter.com" + man.toString());
oAuthConsumer.sign(post);
HttpResponse resp = httpClient.execute(post);
String jsonResponseStr = convertStreamToString(resp.getEntity().getContent());
Log.i(TAG,"response: " + jsonResponseStr);
String id = getFirstMatch(ID_PATTERN,jsonResponseStr);
Log.i(TAG,"id: " + id);
String screenName = getFirstMatch(SCREEN_NAME_PATTERN,jsonResponseStr);
Log.i(TAG,"screen name: " + screenName);
final String url = MessageFormat.format("https://twitter.com/#!/{0}/status/{1}",screenName,id);
Log.i(TAG,"url: " + url);
Runnable runnable = new Runnable() {
public void run() {
((TextView)Main.this.findViewById(R.id.textView)).setText("Tweeted: " + url);
}
};
Main.this.runOnUiThread(runnable);
return resp.getStatusLine().getStatusCode() == 200;
} catch (Exception e) {
Log.e(TAG,"trying to tweet: " + message, e);
return false;
}
}
}
public static String convertStreamToString(java.io.InputStream is) {
try {
return new java.util.Scanner(is).useDelimiter("\\A").next();
} catch (java.util.NoSuchElementException e) {
return "";
}
}
public static String getFirstMatch(Pattern pattern, String str){
Matcher matcher = pattern.matcher(str);
if(matcher.matches()){
return matcher.group(1);
}
return null;
}
于 2013-06-22T08:46:51.657 回答