sql - 如何使用max函数获取db2中的最后一条记录

Question

我想通过使用 max() 函数来获取该表的最后一条记录。

询问

select oafaci, oaorno, min(obfded) ,max(oblded) from mvxcdtpusd.oohead join mvxcdtpusd.ooline on oacono = obcono and oaorno = oborno and oafaci = obfaci and oawhlo = obwhlo where obitno like '19140%' and OBCONO = 888 group by OAFACI, OAORNO

结果

OAFACI  OAORNO      FDate            LDate
812 0000556215  20130109    20130109
812 0000554203  20130102    20130102
812 0000553769  20121017    20121017
812 0000554204  20130130    20130130
812 0000556214  20121024    20121024
812 0000556216  20130206    20130206

从该结果表中-我想要以下数据。

愿望结果

812 0000556216  20130206    20130206

需要帮助以使用 max() 获取最后一条记录

Answer 1

为什么需要使用该max()功能？如果这是家庭作业，您应该在问题中说明这一点。

获得最后一条记录的最佳方法是：

select *
from t
order by date
fetch first 1 row only

Answer 2

试试这个查询，

SELECT  *
FROM    tablename
WHERE   OAFACI = 812 AND
        OAORNO = (SELECT MAX(OAORNO) 
                    FROM tableName
                    WHERE OAFACI = 812)

更新

SELECT  a.*
FROM    tableName a
        INNER JOIN 
        (
            SELECT  OAFACI, MAX(FDATE) max_date
            FROM    tableName
            GROUP   BY OAFACI
        ) b ON  a.OAFACI = b.OAFACI AND
                a.FDATE = b.max_date
-- WHERE    a.OAFACI = 812