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Web 服务返回一个空字符串而不是 NULL，这会导致 Jackson 崩溃。所以我创建了一个自定义解析器，我试图手动解析它？任何想法我怎么能做到这一点？

我在这里做错了什么？我要做的就是像往常一样将 JSON 解析为对象。使用 @JsonProperty 将字段名称添加到我的属性中，因此解析器应该知道如何转换它。

public class InsertReplyDeserializer extends JsonDeserializer<ListingReply> {

    @Override
    public ListingReply deserialize(JsonParser jsonParser, DeserializationContext arg1)
            throws IOException, JsonProcessingException {

        ObjectCodec oc = jsonParser.getCodec();
        JsonNode node = oc.readTree(jsonParser);

        // If service returns "" instead of null return a NULL object and don't try to parse
        if (node.getValueAsText() == "")
            return null;


       ObjectMapper objectMapper = new ObjectMapper();
       ListingReply listingReply = objectMapper.readValue(node, ListingReply.class);


       return listingReply;
    }

}
4

2 回答 2

0

这是我解决它的方法

@Override
public MyObject deserialize(JsonParser jsonParser, DeserializationContext arg1)
        throws IOException, JsonProcessingException {

    ObjectCodec oc = jsonParser.getCodec();
    JsonNode node = oc.readTree(jsonParser);

    if (node.getValueAsText() == "")
        return null;

    MyObject myObject = new MyObject();
    myObject.setMyStirng(node.get("myString").getTextValue());

    JsonNode childNode = node.get("childObject");
    ObjectMapper objectMapper = new ObjectMapper();
    ChildObject childObject = objectMapper.readValue(childNode,
            ChildObject.class);

             myObject.setChildObject(childObject);
             return myObject;
}
于 2013-02-06T02:33:02.260 回答
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I am not sure you need to manually parse response. You solution would work but seems sub-optimal in my opinion. Since it looks like that you are using RestTemplate, you should rather write (or move your parser code to) your own message converter. Then add this converter to your rest template object which will internally deserialize the value for you. Something along the lines,

public class CustomHttpmsgConverter extends  AbstractHttpMessageConverter<Object> {
private ObjectMapper objectMapper = new ObjectMapper();
@Override
protected Object readInternal(Class clazz, HttpInputMessage inputMessage) throws IOException, HttpMessageNotReadableException {
   InputStream istream = inputMessage.getBody();
   String responseString = IOUtils.toString(istream);
   if(responseString.isEmpty()) //if your response is empty
     return null;
   JavaType javaType = getJavaType(clazz);
   try {
       return this.objectMapper.readValue(responseString, javaType);
   } catch (Exception ex) {
    throw new HttpMessageNotReadableException(responseString);
    }
}

//add this converter to your resttemplate
    RestTemplate template = new RestTemplate();
    List<HttpMessageConverter<?>> converters = new ArrayList<HttpMessageConverter<?>>();
    converters.add(new CustomHttpmsgConverter());
    template.setMessageConverters(converters);
于 2013-02-17T23:21:45.247 回答