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我有一个看起来像的 XML

<root status="Y">

<mb mbcode="150201" mbname="AKASH KUNDU" branchid="1" pwd="admin"/>

</root>

我想解析它并单独获取所有数据，我看到了很多示例，但没有一个 XML 看起来像这样

<md>

<mbcode>150201</mbcode>

<mbname>AKASH KUNDU</mbname>

</md>

我知道如何解析这种 XML 请告诉我如何进行那种 XML 解析

到目前为止我已经做了

 DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        InputStream is = new ByteArrayInputStream(responseBody.getBytes("UTF-8"));
        Document doc = db.parse(is);

        NodeList words=doc.getElementsByTagName("root");

        for (int i=0;i<words.getLength();i++) {
            Toast.makeText( getApplicationContext()," " + ((Element)words.item(i)).getAttribute("value"),Toast.LENGTH_SHORT).show();
        }

找到我的解决方案

       //getting the xml Value as per child node form the saved xml
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();

        InputStream is = new ByteArrayInputStream(readString.getBytes("UTF-8"));
        Document doc = db.parse(is);

        NodeList root=doc.getElementsByTagName("root");

        for (int i=0;i<root.getLength();i++) {
            loginStatus = "" + ((Element)root.item(i)).getAttribute("status");
        }


            if(loginStatus.equalsIgnoreCase("Y"))
            {
                NodeList mb=doc.getElementsByTagName("mb");
                for (int i=0;i<mb.getLength();i++) {
                    setMbcode("" + ((Element)mb.item(i)).getAttribute("mbcode"));
                    setMbname("" + ((Element)mb.item(i)).getAttribute("mbname"));
                    branchid  = "" + ((Element)mb.item(i)).getAttribute("branchid");
                    pwd       = "" + ((Element)mb.item(i)).getAttribute("pwd");

            }
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