DotNetZip 中有一个使用 Stream 方法的示例AddEntry
。
String zipToCreate = "Content.zip";
String fileNameInArchive = "Content-From-Stream.bin";
using (System.IO.Stream streamToRead = MyStreamOpener())
{
using (ZipFile zip = new ZipFile())
{
ZipEntry entry= zip.AddEntry(fileNameInArchive, streamToRead);
zip.Save(zipToCreate); // the stream is read implicitly here
}
}
使用 LinqPad 进行的小测试表明可以使用 MemoryStream 构建 zip 文件
void Main()
{
UnicodeEncoding uniEncoding = new UnicodeEncoding();
byte[] firstString = uniEncoding.GetBytes("This is the current contents of your TextBox");
using(MemoryStream memStream = new MemoryStream(100))
{
memStream.Write(firstString, 0 , firstString.Length);
// Reposition the stream at the beginning (otherwise an empty file will be created in the zip archive
memStream.Seek(0, SeekOrigin.Begin);
using (ZipFile zip = new ZipFile())
{
ZipEntry entry= zip.AddEntry("TextBoxData.txt", memStream);
zip.Save(@"D:\temp\memzip.zip");
}
}
}