I'm trying to do something like
strcmp(argv[3], "stdout")
however, in the command line I don't want to type
stdout\0
what's the best way to get rid of the \0 at the end of a string literal?
Thanks!
update:
Thanks guys. I found what's wrong with my code... I should have used
strcmp(argv[3], "stdout") == 0
Thanks @Nicol Bolas
You don't have to type "stdout\0" on the command line. Whichever way your system makes command-line arguments available to your process (it differs by operating system) automatically adds the null character.
As you know, a C-style string is terminated by the null character, which is written in code as '\0'. If that character weren't at the end of the string, a function such as strcmp would keep going well beyond the end of the string, since such a string flouts convention. Since the terminating null character is the C convention, however, the compiler is smart enough to add the null character to the end of a string literal, and the system is smart enough to add the null character to the command-line arguments stored in the memory of a freshly created process. If argc is greater than 3, and the third argument you type on the command-line for your program is "stdout", the call to strcmp(argv[3], "stdout") will return 0 to mean that the two strings match.
You don't need to type \0 in most cases. String literals have a \0 implicitly appended to them, and the C functions that store string data into character arrays will append a \0 on the end (which is why the documentation for many of those functions specifies that your character buffer must have enough space for the string and the null terminator).
字符串字面量由源字符集中的零个或多个字符组成，并用双引号 (") 括起来。字符串字面量表示一系列字符，它们一起形成一个以空字符结尾的字符串。
strcmp 开始比较每个字符串的第一个字符。如果它们彼此相等，则继续以下对，直到字符不同或到达终止空字符。
所以你不需要写\0在最后stdout，你需要比较to的返回strcmp值0：
if (strcmp(argv[3], "stdout") == 0)