我试图弄清楚如何将搜索结果回显到新窗口中。
基本上,用户可以在搜索栏中输入位置、名称等,它会显示 5 个用户结果,即该结果存在多少用户。这是为了限制空间使用。然后,用户可以单击查看更多结果并被带到另一个页面,在该页面上进行查询,并且应该只回显那些在搜索中匹配查询的用户;即“伦敦”的那些用户。
但目前我所有的用户都在显示,我不知道这是为什么。有人可以告诉我哪里出错了。谢谢。
这是我的 search.php 页面,将搜索结果限制为 5:
<?php
//PHP CODE STARTS HERE
if(isset($_GET['submit'])){
// Change the fields below as per the requirements
$db_host="localhost";
$db_username="root";
$db_password="";
$db_name="";
$db_tb_atr_name="display_name";
//Now we are going to write a script that will do search task
// leave the below fields as it is except while loop, which will display results on screen
mysql_connect("$db_host","$db_username","$db_password");
mysql_select_db("$db_name");
$query=mysql_real_escape_string($_GET['query']);
$query_for_result=mysql_query("SELECT *
FROM ptb_stats
WHERE display_name like '%".$query."%' OR location LIKE '%".$query."%' OR age LIKE '%".$query."%' OR nationality LIKE '%".$query."%' OR ethnicity LIKE '%".$query."%' OR hobbies LIKE '%".$query."%' OR local_station LIKE '%".$query."%' LIMIT 5");
echo "<div class=\"search-results\">";
while($data_fetch=mysql_fetch_array($query_for_result))
{
echo "<div class=\"text\"><a href=\"profile.php?id={$data_fetch['user_id']}\" class=\"search\">";
echo "<div class=\"spacing\"><img width=35px height= 30px src=\"data/photos/{$data_fetch['user_id']}/_default.jpg\" class=\"boxgridsearch\"/> ";
echo substr($data_fetch[$db_tb_atr_name], 0,160);
echo "</a></div></div>";
}
echo "<div class=\"morebutton-search\"><a href=\"search_results.php?to=%$query%\" target=\"_blank\" \">+ view more results</a></div>";
mysql_close();
}
?>
这是我的 more_search_results.php 页面,用于显示所有匹配查询的结果:
<?php
$db_host="localhost";
$db_username="root";
$db_password="";
$db_name="";
$db_tb_atr_name="display_name";
//Now we are going to write a script that will do search task
// leave the below fields as it is except while loop, which will display results on screen
mysql_connect("$db_host","$db_username","$db_password");
mysql_select_db("$db_name");
$query=mysql_real_escape_string($_GET['query']);
$query_for_result=mysql_query("SELECT *
FROM ptb_stats
WHERE display_name like '%".$query."%' OR location LIKE '%".$query."%' OR age LIKE '%".$query."%' OR nationality LIKE '%".$query."%' OR ethnicity LIKE '%".$query."%' OR hobbies LIKE '%".$query."%' OR local_station LIKE '%".$query."%'");
echo "<div class=\"search-results\">";
while($data_fetch=mysql_fetch_array($query_for_result))
{
echo "<div class=\"boxgrid caption\"><a href=\"profile.php?id={$data_fetch['user_id']}\"><img width=140px height=180px src=\"data/photos/{$data_fetch['user_id']}/_default.jpg\"><div class=\"cover boxcaption\">"; ?>
<h58><? echo substr($data_fetch[$db_tb_atr_name], 0,160);?></a></h58>
</div>
</div>
<? } ?>