当您有 P、Q、G、Y 和 X 时,.NET Framework (C#) 中是否有生成 40 个字符(公共?)指纹的现有方法,如下所示?
或者有人知道如何实现这一目标吗?
指纹:81F68001 29D928AD BEE41B78 AA862106 CAEAC892
编辑:这是我正在尝试做的一个例子:
string P = "00F35DBCD6D4C296D2FE9118B659D02608B76FAC94BB58B10283F20390E2B259BAC602466162E9EF3E6A1590702CAE49B681A75A878E266F1AFAE0FA89DA5CA44A1551B517A3F80A9D6C630F9E7D239B437F7402DF8055069735894CD9D4708F8777B5E4F3E6A8B2D4EEE50DB2C96BA16D3C81FEB923697D649A8B7771B10E5B3F";
string Q = "00B5AF039839043410E04C35BDDB30679969EBAC8B";
string G = "00F300A68E54DE33A09001E28EC09F2ABF5DAF208774F2514D878D5587D870C91C6DE42B4705078C6F4438765050039C2950B6DE85AFC0D12A7A5C521782CB760918DF68F385A7F177DF50AA6BA0284090454106E422FCAE5390ADC00B859A433430019E970BFA614374DE1FB40C600345EF19DC01A122E4676C614DC29D3DC2FE";
string Y = "00A5317849AF22BA6498F1EF973158C8BDA848BEB074CB141E629C927B18F29C8CE99815001BAAB2931F339B5C52A79BC3DCB0C5962C302707BA6FF1807EEB91D751BA723BB7512C20689AC5E67A1B656CDFD1BA2D4F6A44308509486AA8754B47784FC4C03E546897200388656BA5834A2CC0E18E58454FF60C1BA5411D6F50FD";
我错过了这个中间部分的代码。如何将 P、Q、G、Y 转换为指纹。我尝试了不同的方法,但未能成功生成我在尝试重新创建的应用程序中看到的指纹。
/* convert public key (bigIntKey) into fingerprint */
var bigIntHash = new BigInteger(SHA1.Create().ComputeHash(key.ToByteArray()));
byte[] hash = bigIntHash.ToByteArray();
if (hash.Length != 20)
{
throw new IndexOutOfRangeException();
}
for (int i = 0; i < 5; i++)
{
int lf = BitConverter.ToInt32(hash, i * 4);
Debug.Write(lf.ToString("X") + " ");
}
编辑2:
我试过这个,但这不起作用
// switch P, Q, G, Y and separately to make it work.
byte[] pArr = StringToByteArray(P);
pArr = Tools.Endian.ReverseBytes(pArr);
byte[] qArr = StringToByteArray(Q);
qArr = Tools.Endian.ReverseBytes(qArr);
byte[] gArr = StringToByteArray(G);
gArr = Tools.Endian.ReverseBytes(gArr);
byte[] yArr = StringToByteArray(Y);
yArr = Tools.Endian.ReverseBytes(yArr);
byte[] xArr = StringToByteArray(X);
xArr = Tools.Endian.ReverseBytes(xArr);
byte[] arr = Combine(pArr, qArr, gArr, yArr);
DSACryptoServiceProvider dsa = new DSACryptoServiceProvider();
DSAParameters par = new DSAParameters();
par.P = pArr;
par.Q = qArr;
par.G = gArr;
par.Y = yArr;
par.X = xArr;
dsa.ImportParameters(par);
var xml = dsa.ToXmlString(true);
它将在 ImportParameter 上失败。
谢谢