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正在做一个项目.. Ac-photography.net

需要联系表格方面的帮助。它似乎没有发送,我不断收到“意外错误消息”

<div class="contact_form">
            <div class="done">
                    <b>Thank you!</b> I have received your message. 
                </div>

                <form method="post" action="process.php">
                    <p>name</p>
                    <input type="text" name="name" class="text" />

                    <p>email</p>
                    <input type="text" name="email" class="text" id="email" />

                    <p>message</p>
                    <textarea name="comment" class="text textarea"></textarea>

                    <input type="submit" id="submit" value="send" class="submit-button" />
                </form>

不知道如何在此处放置 PHP。

任何帮助表示赞赏。谢谢你。

    <?php

    //Retrieve form data. 
    //GET - user submitted data using AJAX
    //POST - in case user does not support javascript, we'll use POST instead
    $name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
    $email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
    $comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];

    //flag to indicate which method it uses. If POST set it to 1
    if ($_POST) $post=1;

    //Simple server side validation for POST data, of course, you should validate the email
    if (!$name) $errors[count($errors)] = 'Please enter your name.';
    if (!$email) $errors[count($errors)] = 'Please enter your email.'; 
    if (!$comment) $errors[count($errors)] = 'Please enter your comment.'; 

    //if the errors array is empty, send the mail
    if (!$errors) {

//recipient
$to = 'Your Name <alex.cherkasov@gmail.com>';    // <--------- change your email here
//sender
$from = $name . ' <' . $email . '>';

//subject and the html message
$subject = 'Message from ' . $name; 
$message = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body>
<table>
    <tr><td>Name</td><td>' . $name . '</td></tr>
    <tr><td>Email</td><td>' . $email . '</td></tr>
    <tr><td>Message</td><td>' . nl2br($comment) . '</td></tr>
</table>
</body>
</html>';

//send the mail
$result = sendmail($to, $subject, $message, $from);

//if POST was used, display the message straight away
if ($_POST) {
    if ($result) echo 'Thank you! We have received your message.';
    else echo 'Sorry, unexpected error. Please try again later';

//else if GET was used, return the boolean value so that 
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
    echo $result;   
}

    //if the errors array has values
    } else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="form.php">Back</a>';
exit;
    }


    //Simple mail function with HTML header
    function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";

$result = mail($to,$subject,$message,$headers);

if ($result) return 1;
else return 0;
    }

    ?>
4

1 回答 1

0

JavaScript 部分

表单没有得到正确处理,因为它没有得到任何值。看看contact-form.js

您正在构建data变量:

var data = 'name=' + name.val() + '&email=' + email.val() + '&website=' + website.val() + '&comment='  + encodeURIComponent(comment.val());

但比在 AJAX 调用中,您传递一个带有值的字符串data

//pass the data
data: "data",

试试这个:

//pass the data
data: data,

PHP部分(process.php)

当我像这样简单地调用脚本时:

http://ac-photography.net/process.php?email=test@test.com&name=name&comment=comment

我会收到警告:

警告:mail() [function.mail]: SMTP 服务器响应:550 > 第 72 行 D:\Hosting\6405740\html\process.php 中的地址无效

修复此问题并检查邮件是否正确发送。它将1按预期返回。

于 2013-02-02T12:15:35.837 回答