这是另一个“for xml”问题,但我不确定这是否可以在没有显式模式的情况下完成。如果不能,那我就只能忍受了。
以下是我目前的选择语句:
SELECT
[stream_id] as '@stream_id',
[path_locator] as '@path_locator',
[parent_path_locator] as '@parent_path_locatr',
[file_type] as '@file_type',
[cached_file_size] as '@cached_file_size',
[creation_time] as '@creation_time',
[last_write_time] as '@last_write_time',
[last_access_time] as '@last_access_time',
[is_directory] as '@is_directory',
[is_offline] as '@is_offline',
[is_hidden] as '@is_hidden',
[is_readonly] as '@is_readonly',
[is_archive] as '@is_archive',
[is_system] as '@is_system',
[is_temporary] as '@is_temporary',
[name] as '/name',
dbo.udf_GetChildren(path_locator)
FROM @Merged
WHERE path_locator.GetLevel() = 1
FOR XML PATH'file'), ROOT('files'), TYPE
这将输出以下 xml:
<files>
<file stream_id="" etc...>
<name>NAME</name>
</file>
</files>
这还不错,但我真正想要的是获取name元素的值作为file元素的值。这是一个如此简单的任务,我认为它可以在没有显式模式的情况下完成,但我经常在这些事情上犯错。
I've tried using the '/' marker, but this doesn't seem to have the effect I want (for example Update XML node (in an XML column) in SQL Server 2005 with another column value in the same row).
edit: The desired xml would be simply this:
<files>
<file stream_id="" etc...>NAME</file>
</files>
Many thanks for the help.