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我正在尝试从全球 Dept 商店中抓取大陆/国家/地区的 Dept 商店列表。我正在运行以下代码首先获取大陆，因为我们可以看到 XML 层次结构的方式是，每个大陆的国家不是该大陆的子节点。

> url<-"http://en.wikipedia.org/wiki/List_of_department_stores_by_country"
> doc = htmlTreeParse(url, useInternalNodes = T)
> nodeNames = getNodeSet(doc, "//h2/span[@class='mw-headline']")
> # For Africa
> xmlChildren(nodeNames[[1]])
$a
<a href="/wiki/Africa" title="Africa">Africa</a> 

attr(,"class")
[1] "XMLInternalNodeList" "XMLNodeList"        
> xmlSize(nodeNames[[1]])
[1] 1

我知道我可以在单独的 getNodeSet 命令中执行这些国家/地区，但我只是想确保我没有遗漏任何东西。有没有更聪明的方法可以同时获取每个大陆和每个国家/地区的所有数据？

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1 回答 1

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uisng xpath, 几个路径可以结合| 分隔器。所以我用它来获得同一个列表中的国家和商店。然后我得到第二个国家名单。我使用后一个列表来拆分第一个

url<-"http://en.wikipedia.org/wiki/List_of_department_stores_by_country"
library(XML)
xmltext <- htmlTreeParse(url, useInternalNodes = T)

## Here I use the combined xpath 
cont.shops <- xpathApply(xmltext, '//*[@id="mw-content-text"]/ul/li|
                                   //*[@id="mw-content-text"]/h3',xmlValue)
cont.shops<- do.call(rbind,cont.shops)                  ## from list to  vector


head(cont.shops)                  ## first element is country followed by shops
     [,1]                   
[1,] "[edit] Â Tunisia"     
[2,] "Magasin Général"
[3,] "Mercure Market"       
[4,] "Promogro"             
[5,] "Geant"                
[6,] "Carrefour"            
## I get all the contries in one list 
contries <- xpathApply(xmltext, '//*[@id="mw-content-text"]/h3',xmlValue)
contries <- do.call(rbind,contries)                     ## from list to  vector

    head(contries)
     [,1]                   
[1,] "[edit] Â Tunisia"     
[2,] "[edit] Â Morocco"     
[3,] "[edit] Â Ghana"       
[4,] "[edit] Â Kenya"       
[5,] "[edit] Â Nigeria"     
[6,] "[edit] Â South Africa"

现在我做了一些处理以使用国家/地区拆分 cont.shops。

dd <- which(cont.shops %in% contries)                   ## get the index of contries
freq <- c(diff(dd),length(cont.shops)-tail(dd,1)+1)     ## use diff to get Frequencies
contries.f <- rep(contries,freq)                        ## create the factor splitter


ll <- split(cont.shops,contries.f)

我可以检查结果：

> ll[[contries[1]]]
[1] "[edit]  Tunisia"      "Magasin Général" "Mercure Market"        "Promogro"              "Geant"                
[6] "Carrefour"             "Monoprix"             
> ll[[contries[2]]]
[1] "[edit] Â Morocco"                                                         
[2] "Alpha 55, one 6-story store in Casablanca"                                
[3] "Galeries Lafayette, to open in 2011[1] within Morocco Mall, in Casablanca"
于 2013-02-01T20:18:12.273 回答