5

打字稿 说：

属性“ $1”不存在于类型“ { (pattern: string, flags?: string): RegExp; new(pattern: string, flags?: string): RegExp; }”的值上

可以通过查看TypeScript 0.8.2lib.d.ts附带的定义来解释该类型：

interface RegExp {
    /** 
      * Executes a search on a string using a regular expression pattern, and returns an array containing the results of that search.
      * @param string The String object or string literal on which to perform the search.
      */
    exec(string: string): RegExpExecArray;
    /** 
      * Returns a Boolean value that indicates whether or not a pattern exists in a searched string.
      * @param string String on which to perform the search.
      */
    test(string: string): bool;
    /** Returns a copy of the text of the regular expression pattern. Read-only. The rgExp argument is a Regular expression object. It can be a variable name or a literal. */
    source: string;
    /** Returns a Boolean value indicating the state of the global flag (g) used with a regular expression. Default is false. Read-only. */
    global: bool;
    /** Returns a Boolean value indicating the state of the ignoreCase flag (i) used with a regular expression. Default is false. Read-only. */
    ignoreCase: bool;
    /** Returns a Boolean value indicating the state of the multiline flag (m) used with a regular expression. Default is false. Read-only. */
    multiline: bool;

    lastIndex: number;
}
declare var RegExp: {
    new (pattern: string, flags?: string): RegExp;
    (pattern: string, flags?: string): RegExp;
}

我的问题是如何更改/更新它以允许我参考RegExp.$1,RegExp.$2等？最好是我可以单独声明的东西，因为我不打算直接编辑lib.d.ts（很可能会在更新时被替换）

我试过这个无济于事：

declare var RegExp: {
    new (pattern: string, flags?: string): RegExp;
    (pattern: string, flags?: string): RegExp;
    $1: any;
    $2: any;
    $3: any;
    $4: any;
    $5: any;
    $6: any;
    $7: any;
    $8: any;
    $9: any;    
}

string我想它们实际上应该用类型声明。但无论如何它都不会消除错误。

除此之外，我也很好奇这到底意味着什么（为什么用和不用 ? 声明它new？）：

new (pattern: string, flags?: string): RegExp;
(pattern: string, flags?: string): RegExp;
4

1 回答 1

2

你declare var的很近。接口是开放的，所以你可以写：

interface RegExp {
    $1: string;
    $2: string;
    // etc
}

关于第二个，这是因为new RegExp('[A-Z]')两者RegExp('[A-Z]')都可以创建 RegExp（在类型方面，它既是可调用函数又是构造函数）。

于 2013-02-01T17:23:10.093 回答