php - MYSQL/PHP 选择相同的值

Question

我有一张桌子，上面有我可以订购的产品。

╔═════════╦═════════╗
║ ORDERID ║ INSTORE ║
╠═════════╬═════════╣
║       1 ║       0 ║
║       1 ║       1 ║
║       1 ║       1 ║
║       1 ║       1 ║
║       1 ║       0 ║
║       2 ║       1 ║
║       2 ║       1 ║
║       2 ║       1 ║
╚═════════╩═════════╝

现在我需要获取所有 instore 的订单，所有订单的值都为 1，比如 orderid2。这怎么可能？

期望的结果

╔═════════╗
║ ORDERID ║
╠═════════╣
║       2 ║
╚═════════╝

Answer 1

SELECT  orderID
FROM    tableName
GROUP   BY orderID
HAVING  COUNT(*) = SUM(instore = 1)

• SQLFiddle 演示

Answer 2

SELECT * FROM products p WHERE not exists (select 1 from products where orderid = p.orderid and instore != 1 limit 1)

Answer 3

不确定我是否完全理解你的问题，但

select * from products where instore=1 and orderid=2;

Answer 4

SELECT DISTINCT (

OrderID ) FROM products WHERE Instore =1 且 OrderID 不在 (

SELECT OrderID FROM products WHERE Instore=0 )