2

我正在尝试编写一个程序，该程序采用不同形状的地毯并创建一个带有子类中定义的某些变量的地毯对象。我的代码是

public abstract class Carpet{

protected int area = 0;
protected double unitPrice = 0;
protected double totalPrice = 0.0;
protected String carpetID;

public Carpet(String id, double thisPrice){
    carpetID = id;
    unitPrice = thisPrice;
}

public String getCarpetId(){
    return carpetID;
}

public String toString(){
    String carpet = new String("\n" + "The CarpetId:\t\t" + getCarpetId() + "\nThe Area:\t\t" + area + "\nThe Unit Price\t\t" + unitPrice + "\nThe Total Price\t" + totalPrice + "\n\n");
    return carpet;
}

public abstract void computeTotalPrice();

}

子类是

public class CircleCarpet extends Carpet{

private int radius;

public CircleCarpet(String id, double priceOf, int rad){
    radius = rad;
    super.unitPrice = priceOf;
    computeTotalPrice();

}

public void computeTotalPrice(){
    super.area = radius * radius * 3;
    super.totalPrice = area * unitPrice;
}


public String toString(){
    String forThis = new String("\nThe Carpet Shape:\tCircle\nThe radius:\t\t" + radius + "\n");
    return forThis + super.toString();
}

}

但是每当我尝试编译子类时，我都会收到错误

11: error: constructor Carpet in class Carpet cannot be applied to given types;
public CircleCarpet(String ID, double priceOf, int rad){
                                                       ^


 required: String,double
  found: no arguments
  reason: actual and formal argument lists differ in length
1 error

Tool completed with exit code 1

我不知道该怎么做才能修复它。

4

1 回答 1

9

由于您的超类没有，因此您需要使用super()no-args default constructor,从子类构造函数中显式调用超类构造函数。并不是说这必须是子类构造函数中的第一行。

 public CircleCarpet(String ID, double priceOf, int rad){
    super(ID, priceOf)
    radius = rad;
    super.unitPrice = priceOf;
    computeTotalPrice();

}

一个建议：

遵循 Java 命名约定，变量名应为驼峰式。i.，在这种情况下id比 更合适ID。

于 2013-02-01T15:14:20.637 回答