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我必须使用提供的 Java Web 服务。但问题是此服务需要自定义 HTTPHeaders。我已经寻找解决方案。如果我可以添加参考，我认为这个会起作用。但是当我尝试添加对服务的引用时，出现以下错误：

There was an error downloading 'http://.....'.
The request failed with HTTP status 400: Bad Request.
Metadata contains a reference that cannot be resolved: 'http://......'.
The remote server returned an unexpected response: (400) Bad Request.
The remote server returned an error: (400) Bad Request.
If the service is defined in the current solution, try building the solution and adding    the service reference again.

我认为安全服务器不允许我访问元数据。我已经尝试过MSDN 提供的这个解决方案，并添加了如下自定义标头：

    // Create a request using a URL that can receive a post. 
    WebRequest request = WebRequest.Create("http://....");
    // Set the Method property of the request to POST.
    request.Method = "POST";
    // Create POST data and convert it to a byte array.

    string postData = string.Empty;
    using (StreamReader contentReader = new StreamReader("D:\\test.txt"))
    {
        postData = contentReader.ReadToEnd();
    }

    //Add headers to request
    request.Headers.Add("UserName", "myUserName");
    request.Headers.Add("Password", "myPassword");
    request.Headers.Add("SomeCustomHeader", "myCustomHeaderValue");

    //string postData = "This is a test that posts this string to a Web server.";
    byte[] byteArray = Encoding.UTF8.GetBytes(postData);
    // Set the ContentType property of the WebRequest.
    request.ContentType = "text/xml";
    // Set the ContentLength property of the WebRequest.
    request.ContentLength = byteArray.Length;
    // Get the request stream.
    Stream dataStream = request.GetRequestStream();
    // Write the data to the request stream.
    dataStream.Write(byteArray, 0, byteArray.Length);
    // Close the Stream object.
    dataStream.Close();
    // Get the response.
    WebResponse response = request.GetResponse();
    // Display the status.
    Console.WriteLine(((HttpWebResponse)response).StatusDescription);
    // Get the stream containing content returned by the server.
    dataStream = response.GetResponseStream();
    // Open the stream using a StreamReader for easy access.
    StreamReader reader = new StreamReader(dataStream);
    // Read the content.
    string responseFromServer = reader.ReadToEnd();


    using (StreamWriter resultWriter = new StreamWriter("D:\\result.xml"))
    {
        resultWriter.Write(responseFromServer);
    }

    // Display the content.
    //Console.WriteLine(responseFromServer);
    // Clean up the streams.
    reader.Close();
    dataStream.Close();
    response.Close();

    Console.ReadLine();

它对我有用。我现在可以从服务中获得结果（作为 xml 文件），而且我也有 WSDL。所以我想我可以将这个结果解析为适当的对象。但我希望能够添加服务引用并像普通服务一样使用它。我的意思是使用名称调用方法，而不是使用 SOAP 消息，并将结果作为解析的对象。有什么解决方法吗？提前致谢。

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1 回答 1

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您可以使用 wsdl.exe 工具创建代理类。看看这个http://msdn.microsoft.com/en-us/library/aa529578.aspx

于 2013-02-01T13:32:01.743 回答