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请您通过使用我的代码修复错误来帮助我。当我打印最后一行时,我收到一条语法错误消息:

import math


m_ = 900         # identifier for normal distribution mean   [mm]
s_d = 1          # identifier for normal distribution standard deviation [mm]

print "DISTRIBUTION OF A PLATE WIDTH:" " MEAN", "=",m_,"," "STD DEV", "=", s_d
print ""
print "Using functions from the math library ..."


# The probability density function(pdf) for a normal distribution with mean m_ and 
standard deviation s_d    
ftotal = 0
term = 0.0
count = 0
while abs(term) > 911:
    ftotal += term
    count += 1
    term = term * xx / float(count)


print "x"  "          " " f(x)" "           " " F(x)"
print "890" ""  (1 / ((s_d * (2 * math.pi) ** -0.5)) * math.exp((- (x - m_) ** 2) / (2 * (s_d) ** 2),   0.5 * (1 + math.erf((x - m_) / s_d * m.sqrt(2))
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1 回答 1

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在 while 循环之前定义 x。从最后两行你用 890 表示 x 所以我猜x = 890

x = 890
#your while loop goes here

print "x"  "          " " f(x)" "           " " F(x)"
print "890" ,  (1 / ((s_d * (2 * math.pi) ** -0.5))) * math.exp((- (x - m_) ** 2) / (2 * (s_d) ** 2))  , 0.5 * (1 + math.erf((x - m_) / s_d * math.sqrt(2)))

我不记得确切的公式,但是如果正确输入上述表达式,您将不会收到语法错误。

于 2013-02-01T06:28:44.283 回答