晕那里,
我需要更改 WWW-Authenticate 弹出框的外观/设计以匹配我的网站主题,当用户需要登录到安全页面时,我不希望它显示默认的身份验证弹出框。下面是我用来创建 WWW-Authenticate 弹出窗口的 PHP 脚本。
<?php
$_user_ = 'test';
$_password_ = 'test';
session_start();
$url_action = (empty($_REQUEST['action'])) ? 'logIn' : $_REQUEST['action'];
$auth_realm = (isset($auth_realm)) ? $auth_realm : '';
if (isset($url_action)) {
if (is_callable($url_action)) {
call_user_func($url_action);
} else {
echo 'Function does not exist, request terminated';
};
};
function logIn() {
global $auth_realm;
if (!isset($_SESSION['username'])) {
if (!isset($_SESSION['login'])) {
$_SESSION['login'] = TRUE;
header('WWW-Authenticate: Basic realm="'.$auth_realm.'"');
header('HTTP/1.0 401 Unauthorized');
echo 'You must enter a valid login and password';
echo '<p><a href="?action=logIn">Try again</a></p>';
exit;
} else {
$user = isset($_SERVER['PHP_AUTH_USER']) ? $_SERVER['PHP_AUTH_USER'] : '';
$password = isset($_SERVER['PHP_AUTH_PW']) ? $_SERVER['PHP_AUTH_PW'] : '';
$result = authenticate($user, $password);
if ($result == 0) {
$_SESSION['username'] = $user;
} else {
session_unset($_SESSION['login']);
errMes($result);
echo '<p><a href="?action=logIn">Try again</a></p>';
exit;
};
};
};
}
function authenticate($user, $password) {
global $_user_;
global $_password_;
if (($user == $_user_)&&($password == $_password_)) { return 0; }
else { return 1; };
}
function errMes($errno) {
switch ($errno) {
case 0:
break;
case 1:
echo 'The username or password you entered is incorrect';
break;
default:
echo 'Unknown error';
};
}
function logOut() {
session_start();
session_destroy();
header("Location: index.html");
}
?>
以下是我在需要保护或保护的所有页面中使用的代码。
<?php
require_once 'auth.php';
echo "You've logged in as {$_SESSION['username']}<br>";
echo '<p><a href="?action=logOut">LogOut</a></p>'
?>
请帮助...记住代码工作正常我只想改变外观。感谢先进:)