-2

执行php代码时我不断收到以下错误

解析错误：语法错误，第 37 行 /home/a9440109/public_html/gps_list.php 中的意外 T_CONSTANT_ENCAPSED_STRING

我试图定义字符编码，但仍然出现错误。请让我知道我做错了什么：

 <?php
 header('Content-type: text/html; charset=utf-8');
 //connect to the database

 include ('gps_db_connect.php');

 $query = "SELECT * from gps WHERE server_time > '20130130'";
 $result = mysqli_query($connection, $query) or die(' Error getting data');
 echo $query;


 $row_count = 0;
 $color_switch = 0;
 $td_size=1;
 $td_font='Verdana'';

 echo "<table border = 1 WIDTH=100% CELLSPACING=0 CELLPADDING=1 >";
 echo "<tr> <th>Count</th><th>User/Device ID</th><th>Longitude, Latitude</th>        <th></th> <th> Speed</th>  <th> Direction </th> <th> GPS Date/Time</th> <th> Server Time </th></tr>";
 while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
 if ( $color_switch == 0 ) {
     $bg_color="#FFFFFF";

     $color_switch = 1;
  }

 else {

     $bg_color="#D8D8D8";
         $color_switch = 0;
         }
     $row_count++;
     echo "<tr><td bgcolor=$bg_color> <font size=$td_size face=$td_font>";
     echo $row_count;

         echo "</td><td bgcolor=$bg_color>  <font size=$td_size face=$td_font> &nbsp";
         echo $row['gps_user'];

     echo "</td><td bgcolor=$bg_color>  <font size=$td_size face=$td_font> &nbsp";
     echo $row['gps_lng'].','.$row['gps_lat'];


     echo "</td></tr>";


    }
 echo "</table>";

 ?>
4

2 回答 2

0

替换： $td_font='Verdana'';与 $td_font='Verdana';

于 2013-01-30T20:05:12.310 回答
0 
$td_font='Verdana'';

最后有一个额外的报价。

于 2013-01-30T20:05:44.697 回答